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Mila [183]
3 years ago
14

Which graph best represents the linear function y = 3x -1

Mathematics
1 answer:
vovangra [49]3 years ago
8 0

Answer:

c

Step-by-step explanation:

You might be interested in
Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?
azamat

Answer:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

From the question, the center of the circle is located at (-6,2) and the radius is

r =  \sqrt{10}

We substitute the center and radius to get:

{(x -  - 6)}^{2}  +  {(y - 2)}^{2}  =  {( \sqrt{10} })^{2}

Simplify to obtain:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

7 0
3 years ago
(Brainliest) PLEASE HELPP MEEE
zloy xaker [14]

Answer:

1. According to the angle bisector theorem, DAC = BAC

2. Same kind of goes for BC

3. X must be equal in both equations.   x= 3

9(3) -7 = 20

4(3) +8 = 20

Hope this helped!

8 0
3 years ago
8x^3-8x=1<br> Solve for x
Anit [1.1K]

Step-by-step explanation:

Step-by-step explanation:

\begin{gathered} \frac{8x - 3}{3x} = 2 \\ 8x - 3 = 6x \\ 8x - 6x = 3 \\ 2x = 3 \\ x = \frac{3}{2} \end{gathered}

3x

8x−3

=2

8x−3=6x

8x−6x=3

2x=3

x=

2

3

4 0
3 years ago
X=-1/8y^2 the proabola opens:
Brilliant_brown [7]

I remember CUP -- concave up positive.  Here we have a leading coefficient that's negative, so the cup is upside down, the parabola opens down, an arch not a bowl.


4 0
3 years ago
Use the identity x^3+y^3+z^3−3xyz=(x+y+z)(x^2+y^2+z^2−xy−yz−zx) to determine the value of the sum of three integers given:
RoseWind [281]

Inserting all the given information into the identity, we have

684-3(210)=(x+y+z)(110-107)\implies x+y+z=18

4 0
3 years ago
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