Answer:
x = 12 , y = 10
Step-by-step explanation:
Let x , y are two numbers.
x > y
1 ) Three times the greater is 18 times their
difference
3x = 18( x - y )
x = 6( x - y )
x = 6x - 6y
6y = 5x
y = 5x/6 ——-( 1 )
2 ) 4 times the smaller is 4 less than twice
the sum of the two
4y + 4 = 2 ( x + y )
2y + 2 = x + y
y = x -2 ——( 2 )
From ( 1 ) and ( 2 ) ,
5x/6 = x -2
( 5x /6 ) - x = -2
( 5x - 6x ) /6 = -2
-x = -12
x = 12
Put x = 12 in equation ( 2 ) , we get
y = 12 - 2
y = 10
Therefore ,
x = 12 , y = 10
Answer: The boundary lien should be solid because the inequality indicates that the value “5” is included. Remember: “greater than or equal to; less than or equal to,” as solid lines. While “<;>” are dashed lines.
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0
As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81
Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2
So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2
A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.
3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.
So 2k^2 = 9 + 3k have two rational solutions (Option B).
Hope this Helps! :)
Answer:
a. 
b. 
c. 
d. 
Step-by-step explanation:
Given
Solving (a): When g(x) = 0
Substitute 0 for g(x)
Solve for 8x
Solve for x
Solving (b): when x = 0
Substitute 0 for x
Solving (c): When g(x) = -5
Substitute -5 for g(x)
Solve for 8x
Solve for x
Solving (d): When x = 3
Substitute 3 for x
I belive the answer is 1.
This is because out of 22 ribbon there are 10 which are bue so the probability of blue ribbons is 10/22 and probability of red ribbon is 12/22. So your question was the probability of choosing a red ribbon then a blu ribbon. Because of the word "then" , this means it is simply asking you to add their probablity so after adding 10/22 with 12/22 your answer will come to 22/22 which is equal to 1.
