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PIT_PIT [208]
3 years ago
7

Complete the square to rewrite y = x2 – 6x + 5 in vertex form. Then state whether the vertex is a maximum or a minimum and give

its coordinates. A. Maximum at (3, –4) B. Minimum at (3, –4) C. Minimum at (–3, –4) D. Maximum at (–3, –4)
Mathematics
2 answers:
Allisa [31]3 years ago
6 0
X2 - 6x + 5

= (x - 3)^2 - 9 + 5

= (x - 3)^2  - 4

vertex is a minimum  at  (3, -4)

(
inna [77]3 years ago
6 0

Answer:

B. Minimum at (3, –4)

Step-by-step explanation:

Given is a quadratic function as

y=x^2-6x+5

Considering the first two terms, we find that if we add 9 we can make it a perfect square

Hence add and subtract 9 to right side

y=x^2-6x+9-9+5\\   =(x-3)^2-4

This is in vertex form

Vertex = (3,-4)

Since coefficient of leading term of x is positive, the parabola is open up and hence minimum is at (3,-4)

Option B,

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