Complete the square to rewrite y = x2 – 6x + 5 in vertex form. Then state whether the vertex is a maximum or a minimum and give
its coordinates. A. Maximum at (3, –4) B. Minimum at (3, –4) C. Minimum at (–3, –4) D. Maximum at (–3, –4)
2 answers:
X2 - 6x + 5
= (x - 3)^2 - 9 + 5
= (x - 3)^2 - 4
vertex is a minimum at (3, -4)
(
Answer:
B. Minimum at (3, –4)
Step-by-step explanation:
Given is a quadratic function as

Considering the first two terms, we find that if we add 9 we can make it a perfect square
Hence add and subtract 9 to right side

This is in vertex form
Vertex = (3,-4)
Since coefficient of leading term of x is positive, the parabola is open up and hence minimum is at (3,-4)
Option B,
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2√20=2((√4)(√5)=2((2)(√5)=4√5
now we have
4√5-3√5=1√5=√5
M2=5x+10
.................
5 is the difference.
Note: Minuend - Subtrahend = Difference