Answer:
A
Explanation:
As by 2020 college educated and skilled workers will be short, so companies instead of hiring more skilled workers are relocating their already hired experts and transferring some of their tedious lower skilled tasks to other workers thus reducing their cost of hiring more experts.
By redefining these __high value__ knowledge jobs, they address ___skill__ shortages and _____lower___ costs while enhancing job satisfaction.
Answer:
The correct answer is "$155".
Explanation:
Given:
She sells to miller,
= $90
She sells to baker,
= $145
She sells to consumers,
= $155
Now,
The value added by miller will be:
= 
= 
($)
The value added by the baker will be:
= 
= 
($)
hence,
The GDP in this economy will be:
= 
($)
Answer:
Value of x maximising profit : x = 5
Explanation:
Cost : C(x) = x^3 - 6x^2 + 13x + 15 ; Revenue: R(x) = 28x
Profit : Revenue - Cost = R(x) - C(x)
28x - [x^3 - 6x^2 + 13x + 15] = 28x - x^3 + 6x^2 - 13x - 15
= - x^3 + 6x^2 + 15x - 15
To find value of 'x' that maximises total profit , we differentiate total profit function with respect to x & find that x value.
dTP/dx = - 3x^2 + 12x + 15 = 0 ► 3x^2 - 12x - 15 = 0
3x^2 + 3x - 15x - 15 = 0 ► 3x (x +1) - 15 (x + 1) = 0 ► (x+1) (3x-15) = 0
x + 1 = 0 ∴ x = -1 [Rejected, production quantity cant be negative] ;
3x - 15 = 0 ∴ 3x = 15 ∴ x = 15/3 = 5
Double derivate : d^2TP/dx^2 = - 6x + 12
d^2TP/dx^2 i.e - 6x + 12 at x = 5 is -6(5) + 12 = - 30+ 12 = -8 which is negative. So profit function is maximum at x = 5
