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Tcecarenko [31]
2 years ago
12

Subtract and simplify​

Mathematics
2 answers:
katrin [286]2 years ago
8 0

Answer:

D

Step-by-step explanation:

Since the denominators of both fractions are common, then subtract the numerators leaving the common denominator, that is

\frac{4a+1-2a-7}{a^2-4} = \frac{2a-6}{a^2-4}

daser333 [38]2 years ago
6 0

Answer:

\boxed{\bold{\frac{2a-6}{a^2-4}}}

Explanation:

Apply Rule \bold{\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}}

= \bold{\frac{4a+1-\left(2a+7\right)}{a^2-4}}

Expand \bold{4a+1-\left(2a+7\right): \ 2a-6}

= \bold{\frac{2a-6}{a^2-4}}

Mordancy.

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Answer:

The correct option is commutative property.

Step-by-step explanation:

The expression that Renee is simplifying is:

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It is provided that, Renee recognizes that 7 and \frac{1}{7} are reciprocals, so she would like to find their product before she multiplies by \frac{13}{29}.

The associative property of multiplication states that:

a\times b\times c=(a\times b)\times c=a\times (b\times c)

The commutative property of multiplication states that:

a\times b\times c=a\times c\times b=c\times a\times b

The distributive property of multiplication states that:

a\cdot (b+c)=a\cdot b+a\cdot c

The identity property of multiplication states that:

a\times 1=a\\b\times 1=b

So, Renee should use the commutative property of multiplication to find the product of 7 and \frac{1}{7},

(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})=(7\times\frac{1}{7})\times\frac{13}{29}=\frac{13}{29}

Thus, the correct option is commutative property.

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3 years ago
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Step-by-step explanation:

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