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Temka [501]
3 years ago
12

Give the formula for a function with domain (5, ∞) that has the following properties:

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer:

The area under the curve y = f(x) at x-axis, on the interval x E (5, ∞) is equal to 7.

Step-by-step explanation:

Solution

Given that:

f(x) = 7√x-5

The function of domain is:

D = x-5 > 0

x>5

so,

x← (5, ∞)

Now,

(1) The sequence root function is always known as positive, i.p defined from x E (5, ∞)

i.p =√x-5

Thus,

7/√x-5 >0

Therefore f(x) = 7/√√x-5 which is a positive integer, which is defined in domain x E (5, ∞).

Each value exist a real and unique values of f(x)

Now,

The function f(x) is continuous and over the interval(5, ∞)

Note: Kindly find an attached copy of part to the solution of this given question below

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Answer:

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Step-by-step explanation:

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3 years ago
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The equation of a hyperbola is  x^{2}/9 - y^{2}/4 = 1

What are the steps to Hyperbola equation ?

To find the equation of hyperbola, the following steps must be taken. You need to identify;

  • The coordinate of the center
  • The coordinate of the vertices
  • The coordinate of the foci

The general equation of a hyperbola can be expressed as

x^{2}/a^{2} - y^{2}/b^{2} = 1

From the graph, we have the following parameters

a = 3

a^{2} = 3^{2} = 9

b = 2

b^{2} = 2^{2} = 4

The equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

The vertices = V(+/-a,0) = (+/-3,0)

The center = C(0,0)

The focus = F(+/-C, 0)

Where C^{2} = a^{2}  + b^{2}

C = \sqrt{9 + 4}

C = \sqrt{13}

Focus = F(+/- \sqrt{13}, 0)

The general equation for asymptote = +/- b/a X

= +/-2/3X

Therefore, the equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

Learn more about hyperbola here: brainly.com/question/3405939

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Which of the following best describes the slope of the line below?
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Answer:

D. Negative

Step-by-step explanation:

the line is facing down when looking at it left to right so it is negative.

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alternate interior angles

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