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Given information
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First showing : 1.30pm
Second showing : 4.15 pm
Inbetween : 1/2 hour break
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Find the time the first showing ends
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1/2 hours before 4.15pm
⇒ 30 mins before 4.15pm
⇒ 3.45pm
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Calculate the duration of the firs show
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1.30pm to 3.30pm = 2 hours
3.30pm to 3.45pm = 15 mins
Total duration = 2 hours 15 mins
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Answer: 2 hours 15 mins
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1 Chicken have = 2 legs
1 Cow have = 4 legs
No of cows = x
No of chickens = y
Total no of legs = 4x + 2y = 210.............(1)
Total No of heads = x + y = 84................(2)
x = 84 - y....( from (2) )
Substituting the above equation in (1)
4 ( 84 - y) + 2y = 210
336 - 4y + 2y = 210
336 - 2y = 210
-2y = -126
= y = 63
No of cows = 84-63 = 21
∴ <u><em>Total no of cows = 21</em></u>
<u><em>Total no of chickens = 63</em></u>
Answer:
1375
Step-by-step explanation:
We can just follow what it says.
16 times 3 times 29 = 1392
1392 - 17 = 1375
Answer:
1/10
13/100
4/5
12/25
3/10
63/100
3/5
51/200
2/9
5/11
To prove the last 2 recurring ones:
0.222222... = x
10x = 10 * 0.22222... = 2.222222....
Notice how the decimal part of 10x is the same as for x:
10x - x = 2.2222222... - 0.222222... = 2
10x - x = 9x = 2
x = 2/9
Same procedure for the other one but times by 100 instead:
x = 0.454545...
100x = 45.454545...
100x - x = 45.454545... - 0.454545... = 45
100x - x = 99x = 45
x = 45/99 = 5/11
