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Alchen [17]
3 years ago
12

Solve the following system of equations and select the correct answer below:

Mathematics
1 answer:
Sauron [17]3 years ago
5 0
3x + 3y + 2z = -5 ⇒ 3x + 3y + 2z = -5 ⇒ 3x + 3y + 2z =   -5
1x + 1y + 3z = -4 ⇒ 1x + 1y + 3z = -4 ⇒ 3x + 3y + 9z = -12
3x -  1y + 5z = -8                                                    -7z = 7
                                                                                -7    -7
                                                                                  z = -1
3x + 3y + 2z = -5                                                      
1x + 1y + 3z = -4 ⇒ 1x + 1y + 3z = -4
3x -  1y + 5z = -8 ⇒ 3x -  1y + 5z = -8
                                        4x + 8z = -12     

     4x + 8z = -12
 4x + 8(-1) = -12
       4x - 8 = -12
           + 8    + 8
            4x = -4
             4      4
              x = -1

        3x + 3y + 2z = -5
3(-1) + 3y + 2(-1) = -5
           -3 + 3y - 2 = -5
             3y - 3 - 2 = -5
                  3y - 5 = -5
                      + 5  + 5
                       3y = 0
                        3     3
               (x, y, z) = (-1, 0, -1)
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\mathbb{PROBLEM}

==========================================

\tt{6. Multiply:}{ ( \times  - 4)(x + 5)}

==========================================

\mathbb{ANSWER}

\tt{option. \: (d) \:  \times 2   +  \times  - 20}

==========================================

\mathbb{SOLUTION}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \tt{( \times  - 4)( \times  + 5)}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \tt= x(x + 5) -4(x + 5)

\:  \:   \:  \: \:  \:   \:  \: \:  \:  \:  \:  \:  \tt{ =  \times 2  +  5 \times  - 4 \times  - 20.}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \tt\underline \red{=  \: x2 + x - 20.}

\tt{Answe r  \: is \:  Option  \: (d)}

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