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ASHA 777 [7]
3 years ago
13

Amy baby sat from 7:30 to 11:00 p.m. If Amy was paid $15.75, how much did she earn per hour

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0

$4.50 per hour.

She worked 3 and a half hours. So since her total is $15.75 you'd divide that by 3.5, which works out to $4.50.

Hope this helps! :)  

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Help! Thanks!!!!!!!!!
san4es73 [151]

1)

∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰

AB = 370 m

AC = 510 m

To find BC we can use cosine law.

a² = b² + c² -2bc*cos A

|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)

|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =

|BC| ≈ 553 m


2)

To find ∠ACB, we are going to use law of sine.

sin(∠BAC)/|BC| = sin(∠ACB)/|AB|

sin(76⁰)/553 m = sin(∠ACB)/370 m

sin(∠ACB)=(370*sin(76⁰))/553 =0.6492

∠ACB = 40.48⁰≈ 40⁰


3)

∠BAC = 76⁰

∠ACB = 40⁰

∠CBA = 180-(76+40) = 64⁰


Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰


4)

Shortest distance from A to BC is height (h) from A to BC.


We know that area of the triangle

A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).

Also, area the same triangle

A= (1/2)|BC|*h = (1/2)*553*h.


So, we can write

(1/2)*370*510*sin(76⁰) =(1/2)*553*h

370*510*sin(76⁰) =553*h

h= 370*510*sin(76⁰) / 553= 331 m

h=331 m


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Mack the bug starts at (0,0) at noon and each minute moves one unit right or one unit up. He is trying to get to the point (5,7)
PSYCHO15rus [73]
<span>This is a very nice counting question. Suggestion / Hint: Count how many ways he can get from (0,0) to (5,7) by going through the point (2,3). Then subtract that from ALL POSSIBLE ways he can get from (0,0) to (5,7). Hint for the hint: How many ways he can get from (0,0) to (5,7) by going through the point (2,3)? Well, that's the SUM of how many ways he can get from (0,0) to (2,3) and how many ways he get get from (2,3) to (5,7). Hope this helps! :)</span>
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