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wariber [46]
3 years ago
6

Which equation represents a population of 250 animals that decreases at an annual rate of 21%

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

y= 250( 1-0.21)^x

Step-by-step explanation:

This represents exponential decay

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In an election 32 thousand people voted for Mayor Jackson . A total of 56 thousand people voted in the election . What is the ra
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Answer:

3/7

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The cost of a daily newspaper varies from city to city. However, the variation among prices remains steady with a standard devia
My name is Ann [436]

Answer:

|t| =|-0.96|=0.96< 2.718

since calculated' t' value is less than tabulated value 't'.

we accept null hypothesis at 1 % level of significance.

The data support the claim that the mean cost of a daily news paper is  $1.00

Step-by-step explanation:

<u>Step:-(1)</u>

Given the sample size n = 12

Given Twelve costs yield a mean cost of $0.95 with a standard deviation of $0.18

mean of the sample(x⁻) = $0.95

Standard deviation of sample (S) = $0.18

Given claim that the mean cost of a daily newspaper is $1.00.

The mean of the population 'μ' =  $1.00.

<u>Null hypothesis:</u>-H₀:'μ' =  $1.00.

<u>Alternative hypothesis</u>: H₁:'μ' ≠  $1.00.

<u>level of significance ∝ = 0.01</u>

<u>Step2:-</u>

<u>The test statistic </u>

t = \frac{x^{-}-u_{0}  }{\frac{S}{\sqrt{n} } }

t = \frac{0.95-1 }{\frac{0.18}{\sqrt{12} } }

on calculation, we get

t = -0.96

|t| =|-0.96|=0.96

Degrees of freedom γ = n-1 = 12-1 =11

tₐ =  2.718

Calculated value t = 0.96

Tabulated value t at 0.01 level for 11 degrees for two tailed test = 2.718

since calculated' t' value is less than tabulated value 't'.

<u>conclusion</u>:-

<u>we accept null hypothesis at 1 % level of significance.</u>

<u>The data support the claim that the mean cost of a daily news paper is  $1.00</u>

3 0
3 years ago
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