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AnnyKZ [126]
3 years ago
13

Evaluate 29 -6 × 3.

Mathematics
2 answers:
aleksklad [387]3 years ago
8 0
The answer to your questions is 11 because PEMDAS. () exponents multipication division addition and subtraction. 
Bezzdna [24]3 years ago
6 0
Your answer is 11


Hope this helps


Don't forget to rate and thanks me
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5+m>4 or 7m<-35 please help!
puteri [66]
5+m>4 \ \hbox{or} \ 7m4 \\
m>4-5 \\
m>-1 \\ \\
7m
3 0
4 years ago
Read 2 more answers
HURRY I NEED HELP QUICK
krek1111 [17]

The value of x the function when x = -7.5 is 34.5

<h3>Functions and values</h3>

Functions are written in terms of variables

Given the expression  –3.8x + 6, when the value of x is -7.5, hence;

f(x) =  –3.8x + 6

f(-7.5) = -3.8(-7.5) + 6

f(-7.5) = 28.5 + 6

f(-7.5) = 34.5

Hence the value of x the function when x = -7.5 is 34.5

Learn more on functions here: brainly.com/question/10439235

#SPJ1

4 0
2 years ago
Help me! pleaze help me to do this....give me a step by step answer ..please...
nydimaria [60]
The answer to your question is below this
3 0
3 years ago
?
lilavasa [31]

The count of the equilateral triangle is an illustration of areas

There are 150 small equilateral triangles in the regular hexagon

<h3>How to determine the number of equilateral triangle </h3>

The side length of the hexagon is given as:

L = 5

The area of the hexagon is calculated as:

A = \frac{3\sqrt 3}{2}L^2

This gives

A = \frac{3\sqrt 3}{2}* 5^2

A = \frac{75\sqrt 3}{2}

The side length of the equilateral triangle is

l = 1

The area of the triangle is calculated as:

a = \frac{\sqrt 3}{4}l^2

So, we have:

a = \frac{\sqrt 3}{4}*1^2

a = \frac{\sqrt 3}{4}

The number of equilateral triangles in the regular hexagon is then calculated as:

n = \frac Aa

This gives

n = \frac{75\sqrt 3}{2} \div \frac{\sqrt 3}4

So, we have:

n = \frac{75}{2} \div \frac{1}4

Rewrite as:

n = \frac{75}{2} *\frac{4}1

n = 150

Hence, there are 150 small equilateral triangles in the regular hexagon

Read more about areas at:

brainly.com/question/24487155

4 0
3 years ago
Can someone please help me with this please I really need help
Lubov Fominskaja [6]

Answer:N

Step-by-step explanation:

6 0
3 years ago
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