The correct answer is (B) Adding a dilute solution of HCl
<u>EXPLANATION</u>
The presence of carbonate ions can be tested by adding a dilute acid to the solution. The acid displaces Carbon (IV) oxide from the solution. Using HCl, and a carbonate of metal X.
XCO₃₍s₎ + 2HCl₍aq₎⇒ XCl₂₍aq₎+ H₂O₍l₎ + CO₂₍g₎
The gas produced is tested using calcium hydroxide to confirm whether it is carbon (IV) oxide.
The lost of element arranged in order of increasing Atomic radii is 4) F, CI, Br, I.
the algal population will decrease.
Molarity is defined as the number of moles of solute per 1 L of solvent.
the mass of NaCl in the solution is 87.75 g
number of moles of NaCl is calculated by dividing mass present by molar mass
number of NaCl moles = 87.75 g / 58.44 g/mol = 1.502 mol
the number of NaCl moles in 500 mL is - 1.502 mol
therefore number of NaCl moles in 1000 mL is - 1.502 mol/ 500 mL x 1000 mL/L = 3.004 mol
molarity of NaCl is - 3.004 M
answer is D. 3.00 M
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