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Ratling [72]
2 years ago
5

. Name the solute and solvent in the following: a. 14-karat gold b. corn syrup c. carbonated, or sparkling, water

Chemistry
1 answer:
Elena L [17]2 years ago
8 0

Answer:

a) gold-solvent

silver+ copper-solute

b) solvent- water

solute- sugar

c) solute- CO2

solvent- H2O

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Answer:

\boxed {\boxed {\sf 0.0018 \ mol \ H_2 O }}

Explanation:

First, we need to find the molecular mass of water (H₂O).

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Next, find the amount of moles using the molecular mass we just calculated. Set up a ratio.

0.032 \ g  \ H_2 O* \frac{ 1 \ mol \ H_2 O}{18.0152 \ g \ H_2 O}

Multiply. The grams of H₂O will cancel out.

0.032 * \frac{1 \ mol \ H_2 O}{18.0152 }

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The original measurement given had two significant figures (3,2). We must round to have 2 significant figures. All the zeroes before the 1 are not significant. So, round to the ten thousandth.

The 7 in the hundred thousandth place tells us to round up.

0.0018 \ mol \ H_2 O

There are about <u>0.0018 moles in 0.032 grams.</u>

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