Answer:
Cumulative frequency analysis is the analysis of the frequency of occurrence of values of a phenomenon less than a reference value. The phenomenon may be time- or space-dependent. Cumulative frequency is also called frequency of non-exceedance
Step-by-step explanation:
Answer:
Drawing the first marble would be 4/17 then putting that one aside and picking another green marble would be 3/17
Step-by-step explanation:
It's not 1 that is exactly the problem. It is also 0. And perhaps - 1 although that is a lot trickier than the other two.
Let's start with one. It give 1^1 = 1 for a power of 1. It gives 1^2 = 1 * 1 for a power of 2. It will give 1^100000 = 1 for a power of 100000.
So the base can be 1 but it is known that any power won't change it's value.
The same can be said of 0. 0^1000 = 0^1 = 0. 0^0 is really a bad dude. You won't learn about that for awhile.
(-1)^11 is different from (-1)^10. The first gives -1 and the second gives 1. So you have to be careful with -1.
There is nothing wrong with (1/4)^3. The power of three and the base of 1/4 are fine. The answer is (1/4)*(1/4) * (1/4) = 1/64 which is perfectly good answer.
It works for negatives too. (-1/2)^3 = - 1/8
Answer: Their total budget last year was $40,000.
Step-by-step explanation:
Given : The Smiths spend 6% of their budget on entertainment.
i.e. , The money they spend on entertainment = 0.06 x ( Total budget)
{ 6% is converted to 0.06 , when we divide it by 100 to remove percentage)
Since , this year they plan to spend $2,580 on entertainment.
i.e. 0.06 x ( Total budget ) = $2,580
On dividing both sides by 0.06 , we get
( Total budget ) = $2,580 ÷ 0.06
= $43,000
Thus , their total budget for this year = $43,000
Also, Their total budget this year is $3,000 more than last year.
Therefore , their last year total budget = ( Total budget this year ) - $3000
= $43,000 - $3000
= $40,000
Hence, their total budget last year was $40,000.
Hope this helps! Also can I have brainliest? It’s ok if no :) have a nice day.