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3 years ago

performance determine the slope and the y-intercept given the following linear functions. 1.f(x)=3x-10

Mathematics

1 answer:

Monica [59]3 years ago

3 0

Answer:

Slope: 3

Y-Intercept: -10

Step-by-step explanation:

This equation is in slope-intercept form, it is written as y = mx + b where m is the slope and b is the y-intercept. This means 3 is the slope and -10 is the y-intercept.

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The Pew Research Center Internet Project, conducted on the 25th anniversary of the Internet, involved a survey of 857 Internet u

nydimaria [60]

Answer:

a) 95% confidence interval for the proportion of respondents who say the Internet has been a good thing for them personally:

$0.8801\leq \pi \leq 0.9199$

b) 95% confidence interval for the proportion of respondents who say the Internet has strengthened their relationship with family and friends:

$0.6386\leq \pi \leq 0.7014$

c) 95% confidence interval for the proportion of Internet users who say online groups have helped solve a problem:

$0.5267\leq \pi \leq 0.5933$

d) margin of error for the interval estimates in parts (a) e=0.02, (b) e=0.05, and (c) e=0.06.

Step-by-step explanation:

a) We have a sample proportion of 90% (p=0.90).

The sample size is n=857.

For a 95% CI, the z-value is z=1.96.

The standard deviation for the proportion is:

$\sigma_p=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.9*0.1}{857}}=0.0102$

Then the upper and lower limit of the 95% CI is:

$UL=p+z\cdot \sigma_p=0.9+1.96*0.0102=0.9+0.0199=0.9199\\\\\\LL=p-z\cdot \sigma_p=0.9-1.96*0.0102=0.9-0.0199=0.8801$

b) We have a sample proportion of 67% (p=0.67).

The sample size is n=857.

For a 95% CI, the z-value is z=1.96.

The standard deviation for the proportion is:

$\sigma_p=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.67*0.33}{857}}=0.0160$

Then the upper and lower limit of the 95% CI is:

$UL=p+z\cdot \sigma_p=0.67+1.96*0.0160=0.67+0.0314=0.7014\\\\\\LL=p-z\cdot \sigma_p=0.67-1.96*0.0160=0.67-0.0314=0.6386$

c) We have a sample proportion of 56% (p=0.56).

The sample size is n=857.

For a 95% CI, the z-value is z=1.96.

The standard deviation for the proportion is:

$\sigma_p=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.56*0.44}{857}}=0.0170$

Then the upper and lower limit of the 95% CI is:

$UL=p+z\cdot \sigma_p=0.56+1.96*0.0170=0.56+0.0333=0.5933\\\\\\LL=p-z\cdot \sigma_p=0.56-1.96*0.0170=0.56-0.0333=0.5267$

For a), the relative margin of error is:

$e=\frac{z\sigma_p}{p} =\frac{0.0199}{0.9}= 0.02$

For b), the relative margin of error is:

$e=\frac{z\sigma_p}{p} =\frac{0.0314}{0.67}= 0.05$

For c), the relative margin of error is:

$e=\frac{z\sigma_p}{p} =\frac{0.0333}{0.56}= 0.06$

7 0

3 years ago

WILL MARK BRAINIEST

xxMikexx [17]

X2 +5x

mhm,,
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3 years ago

Read 2 more answers

2x^{3}+30xx^{2} +72x=0 solve using zero product property

Goshia [24]

Answer:

Values of x are: x=0 or x=-3 or x=-12

Step-by-step explanation:

The equation given to solve using zero product property is $2x^3+30x^2+72x=0$

Zero property rule states that if ab=0 then a=0 or b=0

Taking x common from the equation:

$2x^3+30x^2+72x=0\\x(2x^2+30x+72)=0\\$

Applying zero product rule

$x(2x^2+30x+72)=0\\x=0 \ or \ 2x^2+30x+72=0$

Now, solving $2x^2+30x+72=0$

Using quadratic formula to find value of x

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Putting values

$$x=\frac{-30\pm\sqrt{(30)^2-4(2)(72)}}{2(2)}$\\$x=\frac{-30\pm\sqrt{324}}{4}$\\$x=\frac{-30\pm18}{4}$\\$x=\frac{-30+18}{4} \ or \ x=\frac{-30-18}{4}$ \\x=-3 \ or \ x=-12$

So, Values of x are: x=0 or x=-3 or x=-12

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3 years ago

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Oksana_A [137]

Answer:

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3 years ago

I know this isn't math but, is anyone willing to answer or help me at least answer this question?

sergeinik [125]

Answer:

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2 years ago

performance determine the slope and the y-intercept given the following linear functions. 1.f(x)=3x-10​

performance determine the slope and the y-intercept given the following linear functions. 1.f(x)=3x-10