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3 years ago

Solve -x^2+5x-6=2 in quadratic formula

Mathematics

1 answer:

RUDIKE [14]3 years ago

8 0

1). Make your equation equal to 0
2). Then plug in your numbers to the quadratic equation

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A research firm needs to estimate within 3% the proportion of junior executives leaving large manufacturing companies within thr

Y_Kistochka [10]

Answer:

972 junior executives should be surveyed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

35% of junior executives left their company within three years.

This means that $\pi = 0.35$

0.95 = 95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

To update this study, how many junior executives should be surveyed?

Within 3% of the proportion, which means that this is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.35*0.65}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.35*0.65}$

$\sqrt{n} = \frac{1.96\sqrt{0.35*0.65}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.35*0.65}}{0.03})^2$

$n = 971.2$

Rounding up:

972 junior executives should be surveyed.

5 0

3 years ago

What is 267.4 divided by 1/10 ?

kotegsom [21]

I’m personally not to good at adding fractions so I turned 1/10 into 0.1

Then I divided 268.4 by .1 and got 2,674.

7 0

4 years ago

Radius of 8 find the area?

sergejj [24]

C= πr²
C= 3.14×8²
C=3.14×64
C=200.96

5 0

3 years ago

View image below, please help.. thank you!:)

JulijaS [17]

Answer:

-3 -12 -11

Step-by-step explanation

You need the total when added plus 2 to be less than 1 , the graphic is telling you 1 is the highest the answer could be.

3 0

3 years ago

Read 2 more answers

For the first derivative of f(theta)=2cos(theta)+cos^2(theta),

lara31 [8.8K]

Hello,

f(t)=2cos t +cos² t

f'(t)=-2sin t -2cos t*sin t
=-2sin(t)*(1+cos (t))
Maybe we must calculate f'(t)=0 ==>sin(t)(1+cos(t))=0

4 0

3 years ago