The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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Answer:
a =74,321
b. 41,042,523,288
c. 414,832,917
Step-by-step explanation:
because two odd numbers becomes a even number
5 + 5 = 10 7 + 7 = 14 etc
so in the problem you sent 13 and 15 being odd numver will result in a even number when added
Answer:
The height of the tree is H = 77.06 m
Step-by-step explanation:
From Δ ABC
AB = height of the tree
h = 0.9623 x ------- (1)
From Δ ABD
h = 0.77 (x + 20) ----- (2)
Equating Equation 1 & 2 we get
0.9623 x = 0.77 (x + 20)
0.9623 x = 0.77 x + 15.4
x (0.1923) = 15.4
x = 80.08 m
Thus the height of the tree is given by
H = 0.9623 x
H = 0.9623 × 80.08
H = 77.06 m
Therefore the height of the tree is H = 77.06 m
It can't be factored because there are no 2 numbers that when you multiply you get 35 and when you add you get 13.
Answer:
z=5
Step-by-step explanation:
12.2z+ 19.4 = -2.7z + 93.9
14.9z=74.5
z=5
