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anzhelika [568]
3 years ago
14

Can someone help me with this question?

Mathematics
1 answer:
Nikitich [7]3 years ago
4 0
D. 5 5/6

Volume = l * b * h
= 2 1/2 * 3 1/2 * 2/3
= 5/2 * 7/2 * 2/3
= 35/6
= 5 5/6
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Solve G(x) for the given domain.<br> G(x) = 3x2 - 2x - 1<br> G(6) =
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95

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G(6)=3(6)^2-2(6)-1

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The berry-picking boxes at Bingo Berry Farm have square bottoms that are 8 centimeters on each side. Santiago fills his box with
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Read 2 more answers
Consider a drug testing company that provides a test for marijuana usage. Among 310 tested​ subjects, results from 28 subjects w
Naily [24]

Answer:

z=\frac{0.0903 -0.1}{\sqrt{\frac{0.1(1-0.1)}{310}}}=-0.569  

The p value for this case can be calculated with this probability:

p_v =P(z  

Since the p value is higher than significance level we don't have enough evidence to conclude that the true proportion is significantly less than 0.1

Step-by-step explanation:

Information given

n=310 represent th sample selected

X=28 represent the subjects wrong

\hat p=\frac{28}{310}=0.0903 estimated proportion of subjects wrong

p_o=0.1 is the value to verify

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

System of hypothesis

We want to test the claim that less than 10 percent of the test results are wrong ,and the hypothesis are:  

Null hypothesis:p\geq 0.1  

Alternative hypothesis:p < 0.1  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.0903 -0.1}{\sqrt{\frac{0.1(1-0.1)}{310}}}=-0.569  

The p value for this case can be calculated with this probability:

p_v =P(z  

Since the p value is higher than significance level we don't have enough evidence to conclude that the true proportion is significantly less than 0.1

5 0
3 years ago
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