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3 years ago

If triangle DEC congruent to triangle BEC, which is true by CPCTC?

Mathematics

2 answers:

IceJOKER [234]3 years ago

8 0

Answer:

The correct answer is the second one

Step-by-step explanation:

Line BE and ED are congruent because they are the same length and E is the mid line.

Nina [5.8K]3 years ago

8 0

Answer:

second option is correct

Step-by-step explanation:

By the given

ΔDEC≅ΔBEC

which means triangle DEC is congruent to triangle BEC

then by CPCTC (corresponding parts of congruent triangle are congruent)

there every side and angle of DEC will be equal to BEC

⇒BE= DE (by CPCTC)

hence second option is correct

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C) Which of these numbers is a square number?

algol13

The answer is B 9 x 10^5
Because the root of it is 300

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3 years ago

you consistently deposit 250.00 into a savings account on the 15th of each month, and the amount earns a 2.5 APR How much is the

frosja888 [35]

Answer:

Balance of savings account at the end of 3rd month = $753.13

Step-by-step explanation:

Balance at the end of 1st month :

Principal = $250 , Time = 1 month , n = 12 , APR = 2.5%

$\text{Compound Interest = }Principal\times (1+\frac{rate}{n\times 100})^{n\times Time}\\\\=250\times (1+\frac{2.5}{12\times 100})^{12\times \frac{1}{12}}\\\\=\$250.52$

Balance at the end of second month :

Principal = 250 + 250.52

= 500.52

Time = 1 month, APR = 2.5%, n = 12

$\text{Compound Interest = }500.52\times (1+\frac{2.5}{12\times 100})^{12\times \frac{1}{12}}\\\\=\$501.56$

Balance at the end of third month :

Principal = 250 + 501.56

= 751.56

Time = 1 month, APR = 2.5%, n = 12

$\text{Compound Interest = }751.56\times (1+\frac{2.5}{12\times 100})^{12\times \frac{1}{12}}\\\\=\$753.13$

Hence, Balance of savings account at the end of 3rd month = $753.13

6 0

3 years ago

A rectangular box has three of its faces on the coordinate planes and one vertex in the first octant on the paraboloid z=100−x2−

LuckyWell [14K]

The volume as a function of the location of that vertex is

... v(x, y, z) = x·y·z = x·y·(100-x²-y²)

This function is symmetrical in x and y, so will be a maximum when x=y. That is, you wish to maximize the function

... v(x) = x²(100 -2x²) = 2x²(50-x²)

This is a quadratic in x² that has zeros at x²=0 and x²=50. It will have a maximum halfway between those zeros, at x²=25. That maximum volume is

... v(5) = 2·25·(50-25) = 1250

The maximum volume of the box is 1250 cubic units.

7 0

3 years ago

When I have a trinomial with two negatives, is the grouped factoring both negative too?

artcher [175]

Simple...

you have: $y^{2} -7y-18$

(Using the box method)

-->>>

What multiplies to -18 but adds to -7?

-9*2=-18

-9+2=-7

Leaving you with...

(y-9)(y+2)

As we can see the grouped factoring is not all negative...

Thus, your answer.

7 0

4 years ago

The graph of a function is shown on the coordinate plane below. Identify the rate of

GalinKa [24]

<h3>Answer: 7/4</h3>

=========================================================

How to get that answer:

The slope is the rate of change for any linear function.

Apply the slope formula for any two points on the diagonal line.

I'll use the points (-4, -3) and (0, 4)

$m = \frac{y_2-y_1}{x_2-x_1}\\\\m = \frac{4-(-3)}{0-(-4)}\\\\m = \frac{4+3}{0+4}\\\\m = \frac{7}{4}\\\\$

The slope is m = 7/4

This indicates that each time we go up 7 (rise), we also go to the right 4 units (run)

slope = rise/run = 7/4

rise = 7, run = 4

The fraction 7/4 converts to the decimal form 1.75

3 0

3 years ago