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3 years ago

Solve: 3a - 15 = 6 a=

Mathematics

2 answers:

Assoli18 [71]3 years ago

4 0

Answer: $a=7$

Reorder the terms

$-15 + 3a = 6$

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '15' to each side of the equation.

$-15 + 15 + 3a = 6 + 15$

Combine like terms: -15 + 15 = 0

$0 + 3a = 6 + 15\\3a = 6 + 15$

Combine like terms: 6 + 15 = 21

$3a = 21$

Divide each side by '3'.

$a = 7$

DENIUS [597]3 years ago

3 0

Answer:

a=7

Step-by-step explanation:

3a - 15 = 6

3a = 21 -> 6+15

21/3 = 7

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3 years ago

The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in

Stolb23 [73]

Answer:

$ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75$

±0.75 ounce

Step-by-step explanation:

Assuming this complete question: The Wisconsin Dairy Association is interested in estimating the mean weekly consumption of milk for adults over the age of 18 in that state. To do this, they have selected a random sample of 300 people from the designated population. The following results were recorded: xbar=34.5 ounces, s=7.9 ounces Given this information, if the leaders wish to estimate the mean milk consumption with 90 percent confidence, what is the approximate margin of error in the estimate?

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=34.5$ represent the sample mean

$\mu$ population mean (variable of interest)

s=7.9 represent the sample standard deviation

n=300 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=300-1=299$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,199)".And we see that $t_{\alpha/2}=1.653$

And the margin of error is given by:

$ME = 1.653 *\frac{7.9}{\sqrt{300}}= \pm 0.75$

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Answer:

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Step-by-step explanation:

Hello

this is (-10,0) point

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hope this helps

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