Question

What is the empirical formula of an unknown compound that contain 60.3% of magnesium and 39.7% of Oxygen?

Answer 1

Answer:

MgO

Explanation:

Mass of Mg = 60.3 g  

Molar mass of Mg = 24.305 g/mol

Moles of Mg = 60.3 g/ 24.305 g/mol = 2.48 mol

Mass of O = 39.7g  

Molar mass of O = 16 g/mol

Moles of O = 39.7g/ 16 g/mol = 2.48 mol

So the molar ration of Mg:O is 1:1  

Therefore the empirical formula is MgO

Answer 2

The answer is MAGNESIUM OXIDE - MgO.

Good luck :)