All categories

3 years ago

A cup of coffee is considered a A solution B precipitate C solvent D solute

Chemistry

2 answers:

borishaifa [10]3 years ago

8 0

It's either a solution, a solute or, pure goodness in a cup.

masha68 [24]3 years ago

5 0

A. It is a solution because the coffee beans (the solute) are distributed evenly distributed through the water or milk (the solvent)

You might be interested in

55 points plz help

AnnZ [28]

Answer: A FILTERING

Explanation:

WHEN YOU FILTER YOU SEPARATE (sorry for caps) btw can you check out my recent question plz

4 0

3 years ago

A recessive trait is observed when an organism has___recessive gene factors

Bas_tet [7]

The answer is Letter C.<span />

3 0

3 years ago

What would mix the best with water?

yanalaym [24]

Answer:

A)nonpolar molecule

Explanation:

6 0

4 years ago

Which of the following is a form of potential energy?

jok3333 [9.3K]

Answer:

elastic potential energy which is also called spring energy.

4 0

4 years ago

Given the equilibrium constants for the following two reactions in aqueous solution at 25 ∘C HNO2(aq)H2SO3(aq)⇌⇌H+(aq) + NO2−(aq

krok68 [10]

Answer : The value of $K_c$ for the final reaction is, 184.09

Explanation :

The equilibrium reactions in aqueous solution are :

(1) $HNO_2(aq)\rightleftharpoons H^+(aq)+NO_2^-(aq)$ $K_{c_1}=4.5\times 10^{-4}$

(2) $H_2SO_3(aq)\rightleftharpoons 2H^+(aq)+SO_3^{2-}(aq)$ $K_{c_2}=1.1\times 10^{-9}$

The final equilibrium reaction is :

$2HNO_2(aq)+SO_3^{2-}(aq)\rightleftharpoons H_2SO_3(aq)+2NO_2^-(aq)$ $K_{c}=?$

Now we have to calculate the value of $K_c$ for the final reaction.

Now equation 1 is multiply by 2 and reverse the equation 2, we get the value of final equilibrium reaction and the expression of final equilibrium constant is:

$K_c=\frac{(K_{c_1})^2}{K_{c_2}}$

Now put all the given values in this expression, we get :

$K_c=\frac{(4.5\times 10^{-4})^2}{1.1\times 10^{-9}}=184.09$

Therefore, the value of $K_c$ for the final reaction is, 184.09

4 0

3 years ago