Answer:
35.42g
Explanation:
LiOH + KCI → LiCl + KOH
Let us determine the molar mass of LiOH and LiCl. This is illustrated below:
Molar Mass of LiOH = 7 + 16 + 1 = 24g/mol
Molar Mass of LiCl = 7 + 35.5 = 42.5g/mol.
Now, we can obtain the theoretical yield of LiCl as follow:
From the equation above,
24g of LiOH reacted to produce 42.5g of LiCl.
Therefore, 20g of LiOH will react to produce = (20 x 42.5)/24 = 35.42g of LiCl.
From the above calculations, the theoretical yield of LiCl is 35.42g
Yes the answer is c because the atoms are preserved
The balanced reaction would be written as:
C7H6O3 + C4H6O3--->C9H8O4 + HC2H3O2
To determine the percent yield, we need to first determine the theoretical yield if the reaction were to proceed completely. Then, we divide the actual yield that is given to the theoretical yield times 100 percent. The limiting reactant from the reaction would be salicylic acid. We do as follows:
Theoretical yield: 1.23 g C7H6O3 ( 1 mol / 138.21 g ) ( 1 mol C9H8O4 / 1 mol C7H6O3 ) ( 180.157 g / mol ) = 1.60 g <span>C9H8O4 should be produced
Percent yield = 1.39 / 1.60 x 100 = 86.88%
Thus, only 86.88% of the theoretical </span><span>C9H8O4 is being produced.</span>
Easy!
All you have to do is look at the formula.
Lead Sulfide is PbS
Lead Oxide is PbO
Sulfur Dioxide is SO₂
Oxygen is O₂
You would need to balance out the equation, so it would be PbS + O₂ --> PbO + SO₂.
We can balance this out with the following. 2PbS + 2O₂ --> 2PbO + SO₂.
So 0.500 moles of oxygen would be the same conversion rate for PbO so it would also be 0.500 moles of lead oxide (PbO)
Answer:
See below.
Explanation:
Because the copper will be removed from the solution - it will deposit on the electrode. The Cu2+ ions will migrate to the cathode.