Answer:
See explanation
Explanation:
a) The equation of the reaction is;
2Na + Cl2 ------>2NaCl
Number of moles of sodium = 10g/23 g/mol = 0.43 moles
If 2 moles of sodium reacts with 1 mole of Cl2
0.43 moles reacts with 0.43 * 1/2 = 0.215 moles of Cl2
Mass = 0.215 moles of Cl2 *71 g/mol = 15.265 g
b) Equation of the reaction;
HgO -> Hg + O2
1.252 moles of HgO 1.252/32 gmol = 0.039 moles
1 mole of HgO yields 1 mole of oxygen hence
0.039 moles of HgO yields 0.039 moles of oxygen
Mass of oxygen = 0.039 moles * 32 g/mol = 1.248 g
c) Equation of the reaction;
2NaNO3 -----> 2NaNO2 + O2
Number of moles of 128 g of oxygen = 128g/32 g/mol = 4 moles
2 moles of NaNO3 yields 1 mole of oxygen
x moles of NaNO3 yields 4 moles of oxygen
x = 8 moles of NaNo3
Mass of NaNO3 = 8 * 85 g/mol = 680 g of NaNo3
