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BabaBlast [244]
4 years ago
14

Siltstone is made mostly of _____. A : silt B : sand C : shells D : gravel

Computers and Technology
2 answers:
Amanda [17]4 years ago
8 0

Siltstone is mostly made of A) Silt.

frez [133]4 years ago
6 0
The best and most correct answer among the choices provided by the question is the second choice. <span>Siltstone is made mostly of silt. </span>I hope my answer has come to your help. God bless and have a nice day ahead!
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While you are entering a formula in a cell, the cell references and arithmetic operators appear in the _____.
Fofino [41]

Answer:

formula bar

Explanation:

According to my research on Microsoft Excel, I can say that based on the information provided within the question in this situation the cell references and arithmetic operators appear at the top in the section known as the formula bar. This is a toolbar at the top of the Excel software that allows you to add a formula in to cells or charts and is labeled with function symbol (fx).

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

4 0
4 years ago
Creat a new variable brain and assign the string “hello life “
andriy [413]

Answer:

Assuming it is java btw:

public class Answer

{

       public static void main(String[] args)

       {

               String brain = "hello life"

       }

}

8 0
3 years ago
g % Create a program to plot the motion of the ping pong ball with drag. % The program will take inputs for velocity in m/s and
Gala2k [10]

Answer:

% Create a program to plot the motion of the ping pong ball with drag.  

% The program will take inputs for velocity in m/s and angle of launch.

% note that with a high speed camera I estmated a launch speed for a ping

% pong ball could be 30 m/s.

clear all

close all

clc

velStart=input('input the initial velocity in m/sec:   ');

angle=20:5:80;

% convert the degrees into radians so MATLAB likes it

values_angle=angle*pi./180;

rangeAngle=length(values_angle);

hold on

%Lines 1 - 14 are fine

for i=1:rangeAngle

% set initial position and time

x=[];

y=[];

time=[];

vel=velStart;

VelocityX=[];

VelocityY=[];

x(1)=0; % meters

y(1)=.001;  % meters

time(1)=0; % seconds

mass=.00247; %kg  ping pong ball .00247 Kg

g=-9.8; % m/sec^2

c=0.0005; % coefficient of drag where Re is between 10^3 and 10^5

% so I can load an array for plotting

% start to increment the motion

 

index=1;

thisAngle=values_angle(i);

velx=vel*cos(thisAngle);

VelocityX(1)=velx;

vely=vel*sin(thisAngle);

VelocityY(1)=vely;

% set a time step

deltaTime=.001; % seconds

height=y(1);

flag=0;

velFinalX = 0;

velFinalY = 0;

%Don't see any issues here

while height>0 % check that the ball has not hit ground yet (1e-3 to speed things up, It hangs because it never leaves this line, check how height is calculated.)

   index = index+1;

   

   % *******************************************************

   % break velocity into its components

   if index == 2

       velx = vel*cos(thisAngle);

       vely = vel*sin(thisAngle);

   else

       velx = velFinalX;

       vely = velFinalY;

   end

   % *******************************************************

   

   

   % *******************************************************

   % use an if/else statement to check to see if the ball is moving  

   % down (negative). If it is, then drag has an opposite sign

   % as gravity in the acceleration formula.  Otherwise gravity

   % and drag have the same sign. Calculate the new acceleration in the y.

   if vely < 0

       adragy = g + (c*vely.^2)/mass;

       velFinalY = vely + adragy.*deltaTime;

   else

       adragy = g - (c*vely.^2)/mass;

       velFinalY = vely + adragy.*deltaTime;

   end

   % *******************************************************

   

   % *******************************************************

   % Now calculate the acceleration in the x .

   adragx = (-c*velx.^2)/mass;

   % *******************************************************

   

   

   % *****************************************************

   % calculate the new velocity at the end of the time step

   % this will have X and Y components, so you need a variable

   % for each.  One is velFinalX and the other is velFinalY.

   velFinalX = velx + adragx.*deltaTime;

%     velFinalY = vely + adragy.*deltaTime;

   % *******************************************************

   

   

   % ******************************************************

   % Get a new velocity vector and angle given the X and Y

   % The velocity is the variable "vel" and angle is "angle"

   vel = sqrt(velFinalX.^2 + velFinalY.^2);

   angle = atan(velFinalY/velFinalX);

   %*******************************************************

   

   % now save my values at this time step

   VelocityX(index)=velFinalX;

   VelocityY(index)=velFinalY;

   

   % and distance numbers

   distX=VelocityX(index).*deltaTime;

   distY=VelocityY(index).*deltaTime;

   

   % save distance values  

   x(index)=x(index-1)+distX;

   y(index)=y(index-1)+distY;

   height=y(index);

   time(index)=time(index-1)+deltaTime;

   %lines 105-107 are good

   if distY<0&&flag<=1

       if height<.25

           disp(distY)

           fprintf('goal height detected at distance %.2f meters.',x(index));

           flag =2;

           LandingDistance(i)=x(index);

       end

   end

   

end

plot(x,y)

title('distance traveled by ping pong ball in meters')

xlabel('horizontal distance traveled (meters)')

ylabel('vertical distance traveled (meters)')

end

hold off

Explanation:

7 0
4 years ago
Suppose 8 people want to communicate with each other using public key encryption. The communication between any pair of them is
ludmilkaskok [199]

Answer:

The answer is "64"

Explanation:

There has been 1 Private Key 1 Public Key for every person. The private key is used for other app messages. All else uses the Public Key to encrypt messages with that user. Those keys are numerically related. Even if you have 5 users, you will be given 5 Personal keys and 5 Public keys.

  • All user will have a duplicate of other public keys, which indicates (n*n-1) copies of n public keys on different systems to make sure shared contact between all users, plus n private keys.
  • The unique key count is 2n, with n^2 distributed private and public keys on different systems.
  • 8 people,  where 8 is a number, that is equal to n so, n^2 = 8^2 =8 \times 8 = 64
5 0
3 years ago
How many times faster is a computer that measures at
jekas [21]

well Its something soooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

6 0
2 years ago
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