You will use a <select> for this. For example:
<select name="choice">
<option>First</option>
<option>Second</option>
<option>Third</option>
<option>Fourth</option>
<option>Fifth</option>
</select>
Answer:
We cant help with that. Maybe give me more information?
Use PEMDAS.
6 + 3(4) / 6
6 + 12 / 6
6 + 2 = 8
6 / 6 = 1
8 / 1 = 8
I hope this helped.
Answer:
The answer to this question can be defined as follows:
Explanation:
Its Permute-with-all method, which doesn't result in a consistent randomized permutation. It takes into account this same permutation, which occurs while n=3. There's many 3 of each other, when the random calls, with each one of three different values returned and so, the value is= 27. Allow-with-all trying to call possible outcomes as of 3! = 6
Permutations, when a random initial permutation has been made, there will now be any possible combination 1/6 times, that is an integer number m times, where each permutation will have to occur m/27= 1/6. this condition is not fulfilled by the Integer m.
Yes, if you've got the permutation of < 1,2,3 > as well as how to find out design, in which often get the following with permute-with-all chances, which can be defined as follows:
Although these ADD to 1 none are equal to 1/6.
Answer:
see attachment
Explanation:
You have not specified the language, or the details of the I/O form or prompts. Here is a program that does that, written in Wolfram language (the language of Mathematica).
It prompts separately for student name and student score. The minimum score is presumed to be higher than -99999. If only one student name is entered, the second output is that score with no name listed. There is no error checking.
We have elected to keep a list only of the two two scores, and to sort that list again each time a new entry is made.
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The attachment shows the output of the program below the program listing.