Answer:
Explanation:
#include <stdio.h>
int main(void)
{
int num, rem;
printf("Enter a number: ");
scanf("%d", &num);
printf("Roman numerals: ");
while(num != 0)
{
if (num >= 1000) // 1000 - m
{
printf("m");
num -= 1000;
}
else if (num >= 900) // 900 - cm
{
printf("cm");
num -= 900;
}
else if (num >= 500) // 500 - d
{
printf("d");
num -= 500;
}
else if (num >= 400) // 400 - cd
{
printf("cd");
num -= 400;
}
else if (num >= 100) // 100 - c
{
printf("c");
num -= 100;
}
else if (num >= 90) // 90 - xc
{
printf("xc");
num -= 90;
}
else if (num >= 50) // 50 - l
{
printf("l");
num -= 50;
}
else if (num >= 40) // 40 - xl
{
printf("xl");
num -= 40;
}
else if (num >= 10) // 10 - x
{
printf("x");
num -= 10;
}
else if (num >= 9) // 9 - ix
{
printf("ix");
num -= 9;
}
else if (num >= 5) // 5 - v
{
printf("v");
num -= 5;
}
else if (num >= 4) // 4 - iv
{
printf("iv");
num -= 4;
}
else if (num >= 1) // 1 - i
{
printf("i");
num -= 1;
}
}
return 0;
}
Answer:
Check the explanation
Explanation:
The above question can be sovled in the below step by step way:
15 can be written as 16-1 = 24 -1
Therefore, 15 *13 = (24 -1)*13
= 13*24 - 13
Now, when we left shift a number we multiply it by 2k .Where k is no of times we left shifted it.
Therefore, 13*24 = shift 13 to left 4 times
15 * 13 = shift 13 to left 4 times and subtract 13 from it.
