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svetoff [14.1K]
4 years ago
6

____ are the computers that store network software and shared or private user files.

Computers and Technology
1 answer:
kodGreya [7K]4 years ago
3 0
Servers <span>are the computers that store network software and shared or private user files.</span>
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strojnjashka [21]

Answer:

habla en español no te entiendo por favor

6 0
3 years ago
Write two recursive versions of the function minInArray. The function will be given a sequence of elements and should return the
Tomtit [17]

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;//using namespace

int minInArray1(int arr[],int arrSize)//declaring method minInArray1

{

if(arrSize == 1)//use if block to check arrSize value is equal to 1  

{

return arr[0];//return first element of array

}

else //defining else block

{

int max= minInArray1(arr, arrSize-1);//use integer variable max to call method recursively  

if(arr[arrSize-1] < max)//use if block to check array value  

{

max = arr[arrSize-1];//use max to hold array value

}

return max;//return max variable value

}

}

int minInArray2(int arr[], int low, int high)//defining a method minInArray2  

{

if(low == high) //use if to check low and high variable value are equal

{

return arr[low];//return low variable value

}

else //defining else block

{

int minimum = minInArray2(arr, low+1, high);//defining integer variable minimum to call method minInArray2 recursively

if(arr[low] < minimum)

{

minimum = arr[low];//use minimum variable to hold array value

}

return minimum;//return minimum value

}

}

int main()//defining main method

{

int arr[10] = { 9, -2, 14, 12, 3, 6, 2, 1, -9, 15 };//defining an array arr

int r1, r2, r3, r4;//defining integer variable

r1 = minInArray1(arr, 10);//use r1 variable to call minInArray1 and hold its return value

r2 = minInArray2(arr, 0, 9);//use r1 variable to call minInArray2 and hold its return value

cout << r1 << " " << r2 << endl; //use print method to print r1 and r2 variable value

r3 = minInArray2(arr, 2, 5);//use r3 variable to call minInArray1 and hold its return value

r4 = minInArray1(arr + 2, 4); //use r4 variable to call minInArray2 and hold its return value

cout<<r3<< " " <<r4<<endl; //use print method to print r3 and r4 variable value

return 0;

}

Output:

please find the attached file.

Explanation:

In the given code two methods, "minInArray1 and minInArray2" is defined,  in the "minInArray1" it accepts two-variable "array and arrSize" as the parameter, and in the "minInArray2" method it accepts three integer variable "array, low, and high" as the parameter.

  • In the "minInArray1" method, and if the block it checks array size value equal to 1 if the condition is true it will return the first element of the array, and in the else block the max variable is defined, that calling method recursively
  • and store its value.
  • In the "minInArray2" method, an if the block it checks low and high variable value is equal. if the condition is true it will return a low array value. In the next step, the minimum value is defined, which checks the element of the array and uses a low array to store its value.
  • In the main method an array and four integer variable "r1, r2, r3, and r4" is defined, which calls two methods "minInArray1 and minInArray2" and use print method to print its value.
3 0
3 years ago
C++
Nookie1986 [14]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

class Window //defining a class Window

{

private:

int width, height;//defining integer variable

public:

friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters

{

return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values

}  

Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters  

{}

};

int main() //Main method

{

Window w(80,90);//calling class constructor

cout<<w;//print object value

return 0;

}

Output:

a (80 x 90) window

Explanation:

In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.

Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.

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4 years ago
What is the term for movement in particular direction
gladu [14]
The term would be: Velocity 
Velocity is the speed of an object in a particular direction. 
4 0
3 years ago
Read 2 more answers
Hello can you please help with this if you want to thank you!
nikklg [1K]

Answer:

hardware and software is the answer

8 0
3 years ago
Read 2 more answers
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