Answer:
- 39 quarters and 41 nickels
Step-by-step explanation:
Let the number of quarters be x and nickels be y.
<u>Given:</u>
- Quarter is 25 cents
- Nickel is 5 cents
- Number of coins is 80
- Total amount is $11.80 = 1180 cents
<u>We have equations:</u>
- x + y = 80
- 25x + 5y = 1180
<u>Solve the system by elimination, subtract 5 times the first equation from the second one:</u>
- 25x + 5y - 5x - 5y = 1180 - 80*5
- 20x = 780
- x = 780/20
- x = 39
<u>Find the value of y:</u>
- 39 + y = 80
- y = 80 - 39y = 41
<u>Verify:</u>
- 25*39 + 5*41 = 975 + 205 = 1180
Your answer is 21 for this one.
Answer:
The answer is <u>D: lll and IV only</u>
Step-by-step explanation:
Answer:
D. (–3, –6) and (5, 10)
Step-by-step explanation:
The system has equations:
...(1)
and
...(2)
Equate both equations;
Rewrite in standard form:
We factor to obtain:
By the zero product principle;
When x=-3, y=2(-3)=-6
This yields the ordered pair (-3,-6).
When x=5, y=2(5)=10
This yields the ordered pair (5,10).
The correct choice is D.
Answer:
Objective Function: P = 2x + 3y + z
Subject to Constraints:
3x + 2y ≤ 5
2x + y – z ≤ 13
z ≤ 4
x,y,z≥0
Step-by-step explanation:
