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Naya [18.7K]
3 years ago
12

When can we say that a function is continuous?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0
Saying a function f is continuous when x=c is the same as saying that the function's two-side limit at x=c exists and is equal to f(c).
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HELP ME PLEASE!!!
ale4655 [162]

Answer: 45 kilometers

Step-by-step explanation:

The equation to solve this problem is:

$165 = 1.4x + 102

The variable x represents the number of kilometers he travels.

To solve the equation:

Subtract 102 from each side-

63 = 1.4x

Next divide each side by 1.4-

45 = x

Teague needs to run 45 kilometers in order to raise $165.

8 0
4 years ago
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Two angles of a triangle measure 59 degrees and 63 degrees. If the longest side measures 28 centimeters, find the length of the
sertanlavr [38]

Answer:

26.65 or 58

Step-by-step explanation:

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3 years ago
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Free_Kalibri [48]
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Is it to domsmsmmenemamsmmsne
4 0
3 years ago
Can anyone help me!​
zhenek [66]

Answer:

\large \text{$ \sf 2^{-64}$}

Step-by-step explanation:

Given:

\large \text{$ \sf (256)^{-4^{\frac{3}{2}}}$}

This reads as:  256 to the power of "-4 to the power of 3/2".

Therefore, we need to deal with the "-4 to the power of 3/2" first.

Rewrite the 4 as 2²:

\large \text{$ \sf \implies -(2^2)^{\frac{3}{2}}$}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\large \text{$ \sf \implies -2^{\left(2 \times \frac{3}{2}\right)}$}

\large \text{$ \sf \implies -2^{3}$}

Therefore:

\large \text{$ \sf \implies -2^3=(-2)(-2)(-2) = -8$}

Replace "-4 to the power of 3/2" with -8 :

\large \text{$ \sf \implies 256^{-8}$}

Rewrite 256 as 2⁸ :

\large \text{$ \sf \implies (2^8)^{-8}$}

\textsf{Again, apply exponent rule} \quad (a^b)^c=a^{bc}:

\large \text{$ \sf \implies 2^{(8 \times -8)}$}

\large \text{$ \sf \implies 2^{-64}$}

In one complete calculation:

\large\begin{aligned} \sf (256)^{-4^{\frac{3}{2}}} & = \sf (256)^{-(2^2)^{\frac{3}{2}}}\\& = \sf (256)^{-2^{\left(2 \times \frac{3}{2}\right)}}\\& =\sf  (256)^{-2^{3}}\\& = \sf (256)^{-8}\\& \sf = (2^8)^{-8}\\& = \sf 2^{(8 \times -8)}\\& =\sf  2^{-64}\end{aligned}

Learn more about exponent rules here:

brainly.com/question/28211147

brainly.com/question/27959936

4 0
2 years ago
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(6h-2)(2h+6)=0<br> please help
Masja [62]
 Let's solve your equation step-by-step.<span><span><span>(<span><span>6h</span>−2</span>)</span><span>(<span><span>2h</span>+2</span>)</span></span>=0</span>Step 1: Simplify both sides of the equation.<span><span><span><span>12<span>h2</span></span>+<span>8h</span></span>−4</span>=0</span>Step 2: Factor left side of equation.<span><span><span>4<span>(<span><span>3h</span>−1</span>)</span></span><span>(<span>h+1</span>)</span></span>=0</span>Step 3: Set factors equal to 0.<span><span><span><span>3h</span>−1</span>=<span><span><span>0<span> or </span></span>h</span>+1</span></span>=0</span>
answer:h=13 or h=−1
5 0
4 years ago
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