Amount of water in air
Temperature of the area
It’s the process of detecting a change of a objects position relative to its surroundings
Answer:
15.98 L
Explanation:
First, you need to find T1, T2, V1 and V2.
T1 = 25 C = 298.15 K (25C + 273.15K)
T2 = 100 C = 373.15 K (100C + 273.15K)
V1 = 20. L
V2 = ? (we are trying to find)
Next, rearrange to fit the formula
V2 = V1 x T1 / T2
Next, fill in with our numbers
V2 = 20. L x 298.15 K / 373.15 K
Do the math and you should get...
15.98 L
- If you need more help or futher explanation please let me know. I would be glad to help!
Answer: ![[OH^{-}]= 0.01M or 1.0\times 10^{-2}M](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%3D%200.01M%20or%201.0%5Ctimes%2010%5E%7B-2%7DM)
![[H^{+}]= 1.0\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%201.0%5Ctimes%2010%5E%7B-12%7DM)
pH = 12
pOH = 2
Explanation: Calcium hydroxide (
) is a strong base that dissociates completely.
Dissociation equation of Calcium hydroxide is :
1. Concentration of [OH-]
1 mol produces 2 mol OH- ions.
The given solution is 0.005M , then concentration of OH- would be twice the concentration of
![[OH^{-}] = 0.005\times 2](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%200.005%5Ctimes%202%20)
= 0.01M or 
2.Concentration of [H+]
Concentration of [H+] can be calculated by the formula: ![[H^{+}] = \frac{Kw}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7BKw%7D%7B%5BOH%5E%7B-%7D%5D%7D)
kw = ionic product of water and its values is 
[OH-] = 0.01 M or
![[H^{+}] = \frac{(1\times 10^{-14})}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B%281%5Ctimes%2010%5E%7B-14%7D%29%7D%7B%5BOH%5E%7B-%7D%5D%7D)
![[H^{+}] = \frac{(1\times 10^{-14})}{[0.01]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B%281%5Ctimes%2010%5E%7B-14%7D%29%7D%7B%5B0.01%5D%7D)
![[H^{+}] = 1.0\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%201.0%5Ctimes%2010%5E%7B-12%7DM%20)
3. pH value
pH is calculated by the formula : ![pH = -log[H^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%5E%7B%2B%7D%5D)
![pH = -log[1.0\times 10^{-12}]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5B1.0%5Ctimes%2010%5E%7B-12%7D%5D)
pH = 12
4. pOH value
pOH is calculated by the formula : pOH = 14 - pH
pOH = 14 - 12
pOH = 2
pOH can also be calculated by using a different formula which is :
pOH = 2.
Molality = moles of solute /mass of solvent in kg = moles of solute x1000/mass of solvent in gm. Moles of solute = molality x mass of solvent /1000 = 0.95x85.4/1000= 0.0811moles.
