Answer : The value of rate constant at temperature 119 K is 2.46 E-29
Explanation :
As we are the rate law expression as:
![Rate=1.4\times 10^{-2}[NO_2]^2](https://tex.z-dn.net/?f=Rate%3D1.4%5Ctimes%2010%5E%7B-2%7D%5BNO_2%5D%5E2)
..........(1)
The general rate law expression will be:
![Rate=k[NO_2]^2](https://tex.z-dn.net/?f=Rate%3Dk%5BNO_2%5D%5E2)
............(2)
By comparing equation 1 and 2 we get:
Now we have to calculate the rate constant at temperature 119 K.
According to the Arrhenius equation,
or,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate constant at 
= 
= rate constant at 
= ?
= activation energy for the reaction = 80.0 kJ/mole = 80000 J/mole
R = gas constant = 8.314 J/mole.K
= initial temperature = 500 K
= final temperature = 119 K
Now put all the given values in this formula, we get:
![\log (\frac{K_2}{1.4\times 10^{-2}})=\frac{80000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{500}-\frac{1}{119}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7B1.4%5Ctimes%2010%5E%7B-2%7D%7D%29%3D%5Cfrac%7B80000J%2Fmole%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B500%7D-%5Cfrac%7B1%7D%7B119%7D%5D)
Therefore, the value of rate constant at temperature 119 K is 2.46 E-29
Answer:
1. C. remains the same. 2. C. is less than Kc. 3. B. run in the reverse direction to reestablish equilibrium. 4. A. increase.
Explanation:
At constant temperature, the equilibrium concentration has not effect on the equilibrium constant because the rate constants do not change with change in the concentrations or amounts of the reactants or products. Change in the concentration of one reactant or product causes the concentration of the others to change so as to maintain a constant value for the equilibrium constant. On the other hand, the reaction quotient is used to measure the relative amounts of reactants and products during a chemical reaction at any point in time. The value of the reaction quotient shows the direction of the chemical reaction.
Therefore, when 0.31 moles of CCl4(g) are removed from the equilibrium system at constant temperature:
1. the value of Kc remains the same
2. the value of Qc is less than Kc
3. the reaction must run in the reverse direction to reestablish equilibrium
4. the concentration of 
will increase because product will be converted to reactants to reestablish equilibrium.
Answer:
where are those two images which you have sent
Prokaryotes are usually unicellular - and so would not have tissue, organs or organ systems.Some prokaryotes are multicellular, and you could potentially say that they are a tissue (many similar cells working together to perform a task). However, no prokaryotes have organs or organ systems.
