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CaHeK987 [17]
3 years ago
12

Intermolecular forces allow which of the following substances to be the least fluid?

Chemistry
2 answers:
Nataly_w [17]3 years ago
4 0
The correct option is calcite. It is a carbonate mineral of calcium carbonate. Its quite a hard mineral and it not fluid in nature at all. It exhibits both ionic and covalent chemical bonds.
slava [35]3 years ago
3 0
Out of the options, glass is the least fluid. The proof of this also lies in the fact that glass is the most difficult to melt out of all of the mentioned substances, and melting point gives us a rough estimate of the strength of intermolecular forces.
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The reaction 2NO2 → 2NO + O2 obeys the rate law: rate = 1.4 x 10-2[NO2]2 at 500 K . What would be the rate constant at 119 K if
Svet_ta [14]

Answer : The value of rate constant at temperature 119 K is 2.46 E-29

Explanation :

As we are the rate law expression as:

Rate=1.4\times 10^{-2}[NO_2]^2  ..........(1)

The general rate law expression will be:

Rate=k[NO_2]^2       ............(2)

By comparing equation 1 and 2 we get:

k=1.4\times 10^{-2}

Now we have to calculate the rate constant at temperature 119 K.

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at T_1  = 1.4\times 10^{-2}

K_2 = rate constant at T_2 = ?

Ea = activation energy for the reaction = 80.0 kJ/mole = 80000 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 500 K

T_2 = final temperature = 119 K

Now put all the given values in this formula, we get:

\log (\frac{K_2}{1.4\times 10^{-2}})=\frac{80000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{500}-\frac{1}{119}]

K_2=2.46\times 10^{-29}=2.46E-29

Therefore, the value of rate constant at temperature 119 K is 2.46 E-29

8 0
3 years ago
Consider the following system at equilibrium where \Delta H° = 18.8 kJ, and Kc = 9.52×10-2, at 350 K.
slega [8]

Answer:

1. C. remains the same.  2. C. is less than Kc.  3. B. run in the reverse direction to reestablish equilibrium. 4. A. increase.

Explanation:

At constant temperature, the equilibrium concentration has not effect on the equilibrium constant because the rate constants do not change with change in the concentrations or amounts of the reactants or products. Change in the concentration of one reactant or product causes the concentration of the others to change so as to maintain a constant value for the equilibrium constant. On the other hand, the reaction quotient is used to measure the relative amounts of reactants and products during a chemical reaction at any point in time. The value of the reaction quotient shows the direction of the chemical reaction.

Therefore, when 0.31 moles of CCl4(g) are removed from the equilibrium system at constant temperature:

1. the value of Kc remains the same

2. the value of Qc  is less than Kc

3.  the reaction must run in the reverse direction to reestablish equilibrium

4.  the concentration of CH_{4} will increase because product will be converted to reactants to reestablish equilibrium.

7 0
3 years ago
Which of the following elements are more reactive than the others.
Rama09 [41]
The answer is D-sodium!
3 0
2 years ago
( urgent i have limited time ! please help me solve i'll give brainlist )
Xelga [282]

Answer:

where are those two images which you have sent

7 0
2 years ago
Could a prokaryote have tissue , organs , and organ system ?
CaHeK987 [17]
Prokaryotes are usually unicellular - and so would not have tissue, organs or organ systems.Some prokaryotes are multicellular, and you could potentially say that they are a tissue (many similar cells working together to perform a task). However, no prokaryotes have organs or organ systems.
8 0
3 years ago
Read 2 more answers
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