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Oduvanchick [21]
3 years ago
11

The six metals have the work functions, E0.A. Rank these metals on the basis of their cutoff frequency.B. Rank these metals on t

he basis of the maximum wavelength of light needed to free electrons from their surface. C. Each metal is illuminated with 400 nm (3.10 eV) light. Rank the metals on the basis of the maximum kinetic energy of the emitted electrons.1. Cesium: w = 2.1 eV 2. Aliminium: w = 4.1 eV 3. Beryllium: w = 5.0 eV 4. Potassium: w = 2.3 eV 5. Platinium: w = 6.4 eV 6. Magnesium: w = 3.7 eV
Chemistry
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

a) Platinum > Beryllium > Aluminum > Magnesium > Potassium > Cesium

b) Cesium > Potassium > Magnesium > Aluminum > Beryllium > Platinum

c) Cesium > Potassium

Explanation:

We must recall that the frequency of an electromagnetic wave is directly proportional to its energy. Hence as the work function of the metal increases, the minimum frequency required for emission of electrons occur increases accordingly.

Similarly, the maximum wavelength required for electron emission to occur varies inversely as the work function of the metal hence the answer provided.

Lastly, only caesium and potassium has work function less than the energy of the incident photon hence only these two metals experience electron emission with the kinetic energy of electrons emitted from caesium greater than that emitted from potassium.

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A sample of methane gas collected at a pressure of 0.884 atm and a temperature of 6.00 C is found to occupy a volume of 26.5 L.
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Answer:

1.03mole

Explanation:

Given parameters:

Pressure = 0.884 atm

Temperature  = 6°C  = 273 + 6  = 279k

Volume  = 26.5L

Unknown:

Number of moles  = ?

Solution:

To solve this problem, we use the ideal gas equation:

          PV  = nRT

P is the pressure

V is the volume

n is the number of moles

R is the gas constant  = 0.082atmdm³mol⁻¹K⁻¹  

T is the temperature

        n  = \frac{PV}{RT}    = \frac{0.884 x 26.5}{0.082 x 279}    = 1.03mole

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What is the hydronium concentration of a solution with a pH of 3.60
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The answer is A 2.5x10-4M
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4 years ago
A compound is composed of only C, H, and O. The combustion of a .519-g sample of the compound yields 1.24 g of CO_2 and .255 g o
Kay [80]

Answer:

Empirical formula is C₃H₃O.

Explanation:

Given data:

Mass of compound = 0.519 g

Mass of CO₂ = 1.24 g

Mass of H₂O = 0.255 g

Empirical formula = ?

Solution:

%age of C,H,O

C = 1.24 g/0.519 × 12/44 ×100 = 65.5%

H = 0.255 g/0.519 × 2.016/18 ×100 =  5.6%

O = 100 - (65.5+5.6)

O = 28.9%

Number of gram atoms of H = 5.6 / 1.01 = 5.5

Number of gram atoms of O =  28.9 / 16 = 1.81

Number of gram atoms of C = 65.5 / 12 = 5.5

Atomic ratio:

            C                      :        H              :         O

          5.5/1.81              :       5.5/1.81     :       1.81/1.81

            3                      :        3              :        1

C : H : O = 3 : 3 : 1

Empirical formula is C₃H₃O.

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