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USPshnik [31]
4 years ago
10

Factor completely x2 − 49.

Mathematics
2 answers:
masya89 [10]4 years ago
4 0

Answer:

The answer is (x + 7)(x − 7).

Step-by-step explanation:

Given the expression

x^2-49

we have to factorize the above expression completely.

Given expression is

x^2-49=x^2-7^2  →   (1)

By the identity a^2-b^2=(a+b)(a-b)

Put a=x and b=7, we get

x^2-7^2=(x+7)(x-7)

Eq (1) can be written as

x^2-49=(x+7)(x-7)

∴ Option 2 is correct.

NeX [460]4 years ago
3 0
<span>(x + 7)(x − 7) should be your final result</span>
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Find a vector equation and parametric equations for the line. (Use the parameter t.) The line through the point (0, 11, −8) and
NNADVOKAT [17]

Answer:

The vector equation of the line is \overrightarrow {r}=(11j-8k)+t(4i-4j+6k) and parametric equations for the line are x=4t, y=11-4t, z=-8+6t.

Step-by-step explanation:

It is given that the line passes through the point (0,11,-8) and parallel to the line

x=-1+4t

y=6-4t

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The parametric equation are defined as

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Where, (x₁,y₁,z₁) is point from which line passes through and <a,b,c> is cosine of parallel vector.

From the given parametric equation it is clear that the line passes through the point (-1,6,3) and parallel vector is <4,-4,6>.

The required line is passes through the point (0,11,-8) and parallel vector is <4,-4,6>. So, the parametric equations for the line are

x=4t

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Vector equation of a line is

\overrightarrow {r}=\overrightarrow {r_0}+t\overrightarrow {v}

where, \overrightarrow {r_0} is a position vector and \overrightarrow {v} is cosine of parallel vector.

\overrightarrow {r}=(11j-8k)+t(4i-4j+6k)

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3 years ago
Help asap-3(1+6j)=14-j
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Answer:

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Step-by-step explanation:

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Answer:

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