One is colder than the other.
Hope this helps :)
What problem there is no problem explain to me the problem
Answer:
5 hours
Step-by-step explanation:
Our goal here is 3 F because 82+3=85
Ok so you start at 82. For example, you can do 0.6×1=0.6 (no)
0.6×2=1.2 (no)
0.6×3=1.8 (no)
0.6×4=2.4 (no)
0.6×5=3 (yes)
82°+3°=85°
It is given that, ABC BC =6.5cm CA=6.3cm AB=4.8cm Steps involved in construction Step 1: First draw a line segment AB = 4.8cm using pencil and ruler And mark one end A and other end B Step 2: From the point A draw an cm Step 3: From the point B draw an arc of length 6.5 cm Step point of intersection of these arc as C. Step 5: Join A and C & B and C. Now the triangle ABC is ready with BC =6.5cm CA=6.3cm AB=4.8cm
Answer:
a) ∝A ∈ W
so by subspace, W is subspace of 3 × 3 matrix
b) therefore Basis of W is
={
}
Step-by-step explanation:
Given the data in the question;
W = { A| Air Skew symmetric matrix}
= {A | A = -A^T }
A ; O⁻ = -O⁻^T O⁻ : Zero mstrix
O⁻ ∈ W
now let A, B ∈ W
A = -A^T B = -B^T
(A+B)^T = A^T + B^T
= -A - B
- ( A + B )
⇒ A + B = -( A + B)^T
∴ A + B ∈ W.
∝ ∈ | R
(∝.A)^T = ∝A^T
= ∝( -A)
= -( ∝A)
(∝A) = -( ∝A)^T
∴ ∝A ∈ W
so by subspace, W is subspace of 3 × 3 matrix
A ∈ W
A = -AT
A = ![\left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Do%26a%26b%5C%5C-a%26o%26c%5C%5C-b%26-c%260%5Cend%7Barray%7D%5Cright%5D)
=
![+c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]](https://tex.z-dn.net/?f=%2Bc%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%260%5C%5C0%260%261%5C%5C0%26-1%260%5Cend%7Barray%7D%5Cright%5D)
therefore Basis of W is
={
}