Answer:
D. (x – 3)^2 = 17
Step-by-step explanation:
We assume you want an equivalent to x^2 -6x = 8.
We can complete the square by adding the square of half the x-coefficient to both sides of the equation.
x^2 -6x +(-6/2)^2 = 8 +(-6/2)^2
(x -3)^2 = 17 . . . . simplify
9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
Answer: rs 4800, rs 3456
Step-by-step explanation:j
given data:
length of a sid = 48m
cost of ploughing the field = rs 25/m
cost of fencing the field = rs 18/m
solution:
we know a square has four equal sides. so total length of the field is
= m ( 48 + 48 +48 + 48 )
= 192m
cost of ploughing the field
= 192m * rs 25
= rs 4800
cos of fencing the field
= 192m * rs 18
= rs 3456