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deff fn [24]
3 years ago
7

Does (-2)^n/( 3^n+1) converge or diverge?

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0
\left|\dfrac{(-2)^n}{3^n+1}\right|=\dfrac{2^n}{3^n+1}

As n\to\infty, the sequence a_n=\left(\dfrac23\right)^n converges to zero.

If you're talking about the infinite series

\displaystyle\sum_{n\ge0}\dfrac{(-2)^n}{3^n+1}

well we've shown by comparison that this series must also converge because we know any geometric series \sum\limits_n r^n will converge as long as |r|.
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A class of 24 students went on a picnic. They had a choice between having a turkey sandwich or a vegetarian sandwich. Eighteen s
Alekssandra [29.7K]

I believe it is the ratio 3 : 1.

<u>18 students chose the turkey sandwich</u>.

Since the class has a total of 24 students, we can deduce that <u>6 students chose the vegetarian sandwich</u>.

This gives us a ratio of 18 : 6.

When simplified, we get a ratio of 3 : 1.

5 0
3 years ago
6y + 2 + 3 + 14y
hichkok12 [17]

Answer:

20y + 5

Step-by-step explanation:

6y + 2 + 3 + 14y

20y + 2 + 3

20y + 5

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PLEASE MARK BRAINLIEST!

3 0
3 years ago
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8 with a exponent of 2 +7
Lyrx [107]

Answer:

71

Step-by-step explanation:

8²=64

64+7=71

I hope this helps!

8 0
3 years ago
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bixtya [17]

Answer:

No

Step-by-step explanation:

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5 0
3 years ago
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In a theater, there are 4 long rows of chairs,each with an equal number of chairs There are 5 ahort rows of chairs,each with an
Hoochie [10]
<span>There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.

So, total number of chairs in 4 long rows= 4x
Total number of chairs in 5 short rows = 5y
Total number of chairs in the theater on a normal day = 4x + 5y

When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)

When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)

Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
= 4x + 8 + 5y + 15
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Thus we can say the number of chairs increase by 23 as compared to a normal day.
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7 0
3 years ago
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