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deff fn [24]
3 years ago
7

Does (-2)^n/( 3^n+1) converge or diverge?

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0
\left|\dfrac{(-2)^n}{3^n+1}\right|=\dfrac{2^n}{3^n+1}

As n\to\infty, the sequence a_n=\left(\dfrac23\right)^n converges to zero.

If you're talking about the infinite series

\displaystyle\sum_{n\ge0}\dfrac{(-2)^n}{3^n+1}

well we've shown by comparison that this series must also converge because we know any geometric series \sum\limits_n r^n will converge as long as |r|.
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3 years ago
Please I really need help with this
romanna [79]

Answer:

A, 14

Step-by-step explanation:

Assuming that she has a total of d dollars, and spends half of it, then we have 1/2d. She then spends <em>another</em> 6 dollars, and therefore we would subtract. She is left with one dollar.

1/2d-6=1

Working backwards, we can solve for d, her total amount of money:

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<em>I hope this helps! :)</em>

6 0
3 years ago
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3 0
3 years ago
I need help to solve the problem
natta225 [31]

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