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deff fn [24]
2 years ago
7

Does (-2)^n/( 3^n+1) converge or diverge?

Mathematics
1 answer:
hodyreva [135]2 years ago
3 0
\left|\dfrac{(-2)^n}{3^n+1}\right|=\dfrac{2^n}{3^n+1}

As n\to\infty, the sequence a_n=\left(\dfrac23\right)^n converges to zero.

If you're talking about the infinite series

\displaystyle\sum_{n\ge0}\dfrac{(-2)^n}{3^n+1}

well we've shown by comparison that this series must also converge because we know any geometric series \sum\limits_n r^n will converge as long as |r|.
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Solve 4^x+2 = 12 for x using the change of base formula log base b of y equals log y over log b.
valentinak56 [21]

The value of x is 1.66

Step-by-step explanation:

Let use revise the rules of exponential and logarithmic equations

1. If y = b^{x}, then log_{b}(y)=x

2. log_{b}(y) = \frac{log(y)}{log(b)}

Use the rules above to solve the problem

∵ 4^{x}+2=12

- Subtract 2 from both sides

∴ 4^{x}=10

change the exponential equation to logarithmic equation

∴ log_{4}(10)=x

∵ log_{4}(10) = \frac{log(10)}{log(4)}

∴ x = \frac{log(10)}{log(4)}

∴ x = 1.66

The value of x is 1.66

Learn more:

You can learn more about logarithmic function in brainly.com/question/10633485

#LearnwithBrainly

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