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3 years ago

PLEASE HELP ME

Mathematics

2 answers:

quester [9]3 years ago

8 0

Answer:

57π cm³ ≈ 179.07 cm³ [hundredth] or 179.1 cm³ [tenth]

Step-by-step explanation:

Cone Volume = ⅓πr²h

Cylinder Volume = πr²h

__________________

Given:

Cone and Cylinder have a radius of 3 cm.
Cone has a height of 4 cm.
Cylinder has a height of 5 cm.

_____________________

The total volume will be the sum (addition) of the cones volume and the cylinders volume.

Therefore:

Total volume = ⅓πr²(h_1) + πr²(h_2)

Total volume = (⅓(h_1) + (h_2))(πr²)

Total volume = (⅓(4 cm) + (5 cm))(π(3 cm²))

Total volume = (4/3 + 5)(9π) cm³

Total volume = (19/3)(9π) cm³

Total volume = 57π cm³

Total volume = 179.0707812546.. cm³

Total volume ≈ 179.07 cm³ [hundredth] or 179.1 cm³ [tenth]

GenaCL600 [577]3 years ago

3 0

Answer:

Step-by-step explanation:

The base radius is 3

The height of the cylinder is 5

The height of the cone is 4

Add The Numbers

3 + 5 + 4 = 12

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KengaRu [80]

If you know the derivative $f'(x)$ of some function $f(x)$ , you can tell exactly who $f(x)$ is, up to an additive, constant term. In fact, knowing $f'(x)$ , you have

$\displaystyle \int f'(x) = f(x)+c$

In your case, we have

$\dfrac{d}{dx} \sqrt{x+3} = \dfrac{1}{2\sqrt{x+3}}$

So, the integral is almost immediate:

$\displaystyle\int \dfrac{2}{\sqrt{x+3}} = \int \dfrac{4}{2\sqrt{x+3}} = 4\int\dfrac{1}{2\sqrt{x+3}} = 4\sqrt{x+3}+c$

So, up to some constant additive term, our function is $4\sqrt{x+3}+c$

To fix this constant, we know that the function passes through the point (6,10), so we have

$f(6) = 4\sqrt{6+3}+c = 4\sqrt{9}+c=12+c=10 \iff c=-2$

And so our function is $4\sqrt{x+3}-2$

If we want to know when this function equals 6, we simply have to ask $f(x)=6$ and solve for x, so we have

$4\sqrt{x+3}-2=6 \iff 4\sqrt{x+3} = 8 \iff \sqrt{x+3} = 2 \iff x+3=4 \iff x = 1$

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3 years ago

Name the angle pairs that are vertical angles.

andreyandreev [35.5K]

Answer:

A and C

Step-by-step explanation:

Vertical angles are angles that are created when two lines cross. They are angles opposite from each other. (another way of saying it:) Vertical angles are angles opposite each other where two lines cross.

Hope this helps! :)

4 0

3 years ago