3 quarters and a dime a nickel and 4 pennies
X = y + 3
2x + y = 9
Solution..
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Substitute for x=y+3 in the second equation...
2x+y = 9
2(y+3)+y=9
2y+6+y=9
3y+6=9
3y=9-6
3y=3
y=3/3
y=1....
Substitute for y=1 in the first equation...
x=y+3
x = 1+3
x=4..
Am sure the answer is quite evident now...
No solutions exist. Set the function equal to 0. x^2= -25. There are no real solutions to this equation.
The answer is C. 45. Here's the work to prove it: c = correct answer, i = incorrect answer;
-2(c + i = 50)
2c - 3i = 75
-2c - 2i = -100
-5i/-5 = -25/-5
i = 5
c + 5 - 5 = 50 - 5
c = 45
Answer:
which class are you which class question is this
