All categories

3 years ago

Simplificati fractile urmatoare pana cand obtinem fractii ireductibile:

Mathematics

2 answers:

rosijanka [135]3 years ago

5 0

Answer:

Step-by-step explanation:

mr Goodwill [35]3 years ago

4 0

It 1224 12 thanks hope I hlpjd vfXbkn

You might be interested in

elixir [45]

The first one. Hope this helps
Be glad to tell me if it’s correct or not

7 0

3 years ago

3х + 9y - 8x - 2y +7

Sonja [21]

Answer:

-5x+7y+7

Step-by-step explanation:

3х + 9y - 8x - 2y +7 can be written like the equation below to help solve it

3x-8x+9y-2y+7

=-5x+7y+7

7 0

3 years ago

Al obtener el valor de lo que costará la fiesta de graduación para tu grupo te das cuenta que el lugar que decidieron alquilar p

dybincka [34]

Explicación paso a paso:

Debemos buscar el costo de cada boleto y la cantidad de personas que deben ir.

Dada la función que da forma al comportamiento expresado como;

f (x) = (-2x) ^ 2 + 80x + 300 donde;

x es el costo de cada boleto

f (x) es el número de personas que deben ir

Para obtener x, usaremos la expresión;

x = -b / 2a

De la ecuación cuadrática dada, a = -2, b = 80 yc = 300

Sustituir;

x = -80/2 (-2)

x = -80 / -4

x = 80/4

x = 20

Por lo tanto, el boleto cuesta $ 20.

Lo siguiente es obtener la cantidad de personas que deben ir. Para conseguirlo, sustituiremos x = 20 en la expresión modelada como se muestra;

f (x) = (-2x) ^ 2 + 80x + 300

f (20) = (-2 (20)) ^ 2 + 80 (20) +300

f (20) = (-40) ^ 2 + 1600 + 300

f (20) = 1600 + 1600 + 300

f (20) = 3500

Por lo tanto, 3500 personas tienen que ir

8 0

3 years ago

Can someone help me with this math problem

zepelin [54]

Answer:

$50.50 = 18 + 5n

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

fter production, a computer component is given a quality score of A, B, and C. On the average U of the components were given a q

RoseWind [281]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question some of the data is missing so, its correct question is defined in the attached file please find it.

Let

A is quality score of A

B is quality score of B

C is quality score of C

$\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\$

Let F is a value of the content so, the value is:

$\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\$

Now, we calculate the tooling value:

$\to p[\frac{C}{F}]$

using the baues therom:

$\to p[\frac{C}{F}] = \frac{p[C] \times p[\frac{F}{C} ]}{p[A] \times p[\frac{F}{A}] + p[B] \times p[\frac{F}{B}]+p[C] \times p[\frac{F}{C}] }$

$= \frac{ 0.17 \times 0.14 }{0.55 \times 0.15 + 0.28 \times 0.12 + 0.17 \times 0.14 } \\\\= \frac{0.0238}{0.0825 + 0.0336 + 0.0238} \\\\= \frac{0.0238}{0.1399} \\\\=0.1701$

7 0

3 years ago