1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
makkiz [27]
3 years ago
15

HELP NEEDED BRAINLIEST AND 5 STAR Is it posible to make a triangle with 3 feet, 8 feet, and 4 feet. Explain why or why not plzzz

zzz.z
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

Answer:

No, IMPOSSIABLE

Step-by-step explanation:

According to the first triangle inequality theorem, the lengths of any two sides of a triangle must add up to more than the length of the third side. In you case 3+4=7.  7 is less than 8.

You might be interested in
Find the percent of change and describe it as an increase or decrease. If necessary, round to the nearest tenth.
Zanzabum
B 25%percent increase is the answer
5 0
3 years ago
Sewing patterns recommended buying extra fabric in case of mistakes. Darlene bought 7 yards of fabric, plus 20% extra fabric. Ch
Debora [2.8K]

Answer:

Darlene bought more fabric

Darlene bought 3.4 yards more

Step-by-step explanation:

Darlene = 7 yards + 20% extra

= 7 yards + (20% of 7 yards)

= 7 + (20% × 7)

= 7 + (0.2 × 7)

= 7 + 1.4

= 8.4 yards

Chris = 4 yards + 25% of 4 yards

= 4 yards + (25% of 4 yards)

= 4 + (25% × 4)

= 4 + (0.25 × 4)

= 4 + 1

= 5 yards

Darlene bought more fabric

How much more?

Darlene - Chris

= 8.4 yards - 5 yards

= 3.4 yards

Darlene bought 3.4 yards more

6 0
3 years ago
Find the value of k for which the line y = kx + 6 is a tangent to the curve x^2 + y^2 – 10x + 8y = 84
guajiro [1.7K]

Answer:

k = 1/2

Step-by-step explanation:

input y = kx +6 into the equation of the curve x² + y² – 10x + 8y = 84

x² + (kx + 6)² - 10x + 8(kx + 6) = 84

expand:

x² + k²x² + 12kx + 36 - 10x + 8kx + 48 = 84

simplify by collecting like terms:

x² + k²x² + 20kx - 10x + 84 = 84

subtract 84 on both sides to bring it to the left:

x² + k²x² + 20kx - 10x + 84 - 84 = 0

x² + k²x² + 20kx - 10x = 0

factorise out x:

x²(1 + k²) + x(20k - 10) = 0

using the discriminant b² - 4ac where b is 20k - 10, a is 1 + k² and c is 0, substitute them in the formula b² - 4ac:

b² - 4ac

(20k - 10)² - 4(1 + k²)(0) = 0

the part highlighted in bold is gone because it's all multiplied by 0, so we are left with (20k - 10)² = 0

(20k - 10)² is the same as

(20k - 10)(20k - 10)

equate both to 0

20k - 10 = 0 and 20k - 10 = 0

add 10 on both sides

20k = 10 and 20k = 10

divide 20 on both sides

k = 10/20 and k = 10/20 which are both the same

10/20 is simplified to 1/2

k = 1/2

5 0
2 years ago
What is 4 percent of 1425
hammer [34]
4% outta 1425 is 57| The amount is 57.
8 0
4 years ago
Read 2 more answers
If the revenue for the week is 2000 and labor costs consists of two workers earning 8 per hour who work 40 hours each what is la
Valentin [98]
2 * (40 * 8) = 640

\frac{640}{2000} *100=32 percent
7 0
3 years ago
Other questions:
  • How do you find a frequency of a class when the relative frequency is given
    13·1 answer
  • How do you turn 85 into 9.2
    11·1 answer
  • Helpppppppp please ugh
    11·2 answers
  • (08.04 MC) Find the sum of an 8-term geometric sequence when the first term is 7 and the last term is 114,688 and select the cor
    7·1 answer
  • The rectangular prism shown has a length of 5 cm, a height of 3 cm, and a width of 4 cm. What is the surface area of this prism?
    12·2 answers
  • Can I get help with this
    15·1 answer
  • Solve for the following variable: y = mx b, solve for x
    14·1 answer
  • Which equation can be used to find the answer?
    11·2 answers
  • If anils hieght was 150cm and amans height was 100cm then the ratio of their heights would be​
    11·1 answer
  • You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on con
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!