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Mademuasel [1]
3 years ago
14

Marta is solving the equation

Mathematics
1 answer:
ehidna [41]3 years ago
7 0

Well Marta is still like that if you can Marta good luck

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An equilateral triangle has perimeter P. The length of one side is P/3. Which expression is equivalent to the length on one side
irina1246 [14]

Answer: 3\times \dfrac{P}{3}=P

Step-by-step explanation:

Given

The perimeter of one equilateral triangle is P

The lengths of the equilateral triangle are equal

Suppose x is the length of each side

\therefore 3\times x=P\\\\\Rightarrow x=\dfrac{P}{3}

i.e.

\Rightarrow 3\times \dfrac{P}{3}=P

3 0
3 years ago
Euglena are _______.<br><br> A heterotrophs<br><br> B autotrophs
Nataliya [291]

Answer:

they are both

if that is an option

7 0
3 years ago
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8x+3y=4 <br> -7x+5y=-34 <br><br> Elimination using multiplication
irga5000 [103]

Answer:

x= 2    and y = -4

Step-by-step explanation:

8x + 3y = 4 ---------------------------------(1)

-7x + 5y = -34 -----------------------------(2)

Multiply through equation (1) by 5 and multiply through equation(2) by 3

40x + 15y = 20 ----------------------------(3)

-21x + 15y =-102----------------------------(4)

Subtract equation (4) from equation (3)

61x = 122

Divide both-side of the equation by 61

61x/61 = 122/61

(At the left-hand side of the equation 61 will cancel-out 61 leaving us with just x, while at the left-hand side of the equation 122 will be divided by 61)

x = 122/61

x=2

Substitute x= 2 into equation (1)

8x + 3y = 4

8(2) + 3y = 4

16 + 3y = 4

Subtract 16 from both-side of the equation

16-16 + 3y = 4-16

3y = -12

Divide both-side of the equation by 3

3y/3 = -12/3

y = -4

x= 2    and y = -4

4 0
3 years ago
Read 2 more answers
A nick on the edge of a CD rotates to (−6, 5) during one song when represented graphically.
Allisa [31]
By definition, the sine of an angle is given by:
 sin \alpha =  \frac{C.O}{h}
 Where,
 C.O: opposite leg
 h: hypotenuse
 The hypotenuse is given by:
 h =  \sqrt{(-6)^2+(5)^2}
 h =  \sqrt{(61}
 So, replacing values we have:
 sin \alpha = \frac{5}{\sqrt{61}}
 Rewriting we have:
 sin \alpha = \frac{5\sqrt{61}}{61}
 Answer:
 
the sine value of this function is:
 
A)5 times square root 61 over 61
6 0
3 years ago
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What is the lowest value of the range of the function shown on the graph?
insens350 [35]
The complete question in the attached figure

we know that
the range is the y-value  of the function
so
the lowest y-value on this graph is y = -2.

the answer is
y=-2

5 0
3 years ago
Read 2 more answers
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