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3 years ago

9

A path is 0.75m wide mrkessel extends the width by placing blocks 20cm wide on each side of the path what is the new width of th

e path in meters

1 answer:

daser333 [38]3 years ago

8 0

It will be .95m wide
20cm = .2m

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Suppose H is in the interior of right angle JAK. The measure of JAH = (3x-8)º and the measure of KAH = (x+2)º. Find the measure

poizon [28]

Ok so since its a right angle it adds up to 90° therefore 3x-8+x+2=90 4x-6=90 4x=96 x=24 so JAH=3(24)-8 JAH=64°

7 0

3 years ago

Find the area of the part of the sphere x2 + y2 + z2 = 100z that lies inside the paraboloid z = x2 + y2.

vekshin1

$x^2+y^2+z^2=100z\iff x^2+y^2+(z-50)^2=50^2$

The surface of interest can be parameterized by

$\mathbf r(u,v)=\begin{cases}x(u,v)=50\cos u\sin v\\y(u,v)=50\sin u\sin v\\z(u,v)=50(\cos v+1)\end{cases}$

with $0\le u\le2\pi$ and $0\le v\le\arccos\dfrac{49}{50}$ .

The area of the surface $S$ is given by the surface integral

$\displaystyle\iint_S\mathrm dA=\iint_T\left\|\mathbf r_u\times\mathbf r_v\right\|\,\mathrm du\,\mathrm dv$

We have

$\|\mathbf r_u\times\mathbf r_v\|=50^2\sin v$

so the area is given by the double integral

$\displaystyle50^2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\arccos(49/50)}\sin v\,\mathrm dv\,\mathrm du=100\pi$

6 0

4 years ago

Can some help me with the question below I don't know the answer

Alika [10]

Answer:

y=4

Step-by-step explanation:

in a 45-45-90 triangle sides a and b are equal and the hypotenuse is $a\sqrt{2}$

so in this case y is a leg, so it is 4

in case there is a part two where they ask what x is, it would be $4\sqrt{2}$

4 0

3 years ago

63 :(5X - 3X - 1)=21:3

Crazy boy [7]

Answer:

x = 5

Step-by-step explanation:

Given that,

$63:(5x-3x-1)=21:3\\\\or\\\\\dfrac{63}{(5x-3x-1)}=\dfrac{21}{3}\\\\\dfrac{63}{(2x-1)}=7$

Cross multiplying both sides,

$63=7(2x-1)\\\\9=2x-1$

Taking like terms together,

$10=2x\\\\x=5$

So, the value of x is equal to 5.

8 0

3 years ago

Mr. Johnson currently has a square garden. He wants to redesign his garden and make it into a rectangle with a length that is 5

AlekseyPX

Answer:

Width of the rectangle = 10 feet

Length of the rectangle = 25 feet

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

Let

Width of the rectangle = x feet

Length of the rectangle = 3x - 5 feet

Perimeter of the rectangle = 70 feet

Perimeter of a rectangle = 2(length + width)

70 = 2{x + (3x - 5)}

70 = 2{x + 3x - 5}

70 = 2(4x - 5)

70 = 8x - 10

70 + 10 = 8x

80 = 8x

Divide both sides by 8

x = 80 / 8

= 10

Width of the rectangle = 10 feet

Length of the rectangle = 3(10) - 5

= 30 - 5

= 25 feet

6 0

2 years ago