Write the equation of a Quadratic Function that has its vertex at (-3, 2) and goes through the point (-1, -2).

Mathematics

1 answer:

Mariulka [41]3 years ago

7 0

Answer:

$y = a {(x - b)}^{2} + c \\ vertrix \: \binom{b}{c} = \binom{ - 3}{2} \\ point \: \binom{ - 1}{ - 2} \\ - 2 = a {(( - 1) - ( - 3))}^{2} + 2 \\ - 4 = a4 \\ \therefore \: a = - 1 \\ y = - {(x + 3)}^{2} + 2 \\y = - {x}^{2} - 6x - 9 + 2 \\ y = - {x}^{2} - 6x - 7$

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