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romanna [79]
4 years ago
13

Prove that if a number squared is even then the number is even

Mathematics
1 answer:
Varvara68 [4.7K]4 years ago
5 0
2^=4, 4^=16, 6^=36, any even number times itself will result in an even number.
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Please help!
egoroff_w [7]

Answer:

see explanation

Step-by-step explanation:

25

The diagonals of a kite are perpendicular to each other, hence

∠EHF = 90°

The sum of the 3 angles in a triangle = 180°

In ΔEHF

∠1 + ∠2 + 90 = 180, that is

42 + ∠2 + 90 = 180

132 + ∠2 = 180 ( subtract 132 from both sides )

∠2 = 48°

26

DE and DG are congruent sides, hence

4x - 2 = 22.5 ( add 2 to both sides )

4x = 24.5 ( divide both sides by 4 )

x = 6.125

27

∠A and ∠C are congruent, hence

∠A = ∠C = 82°

The sum of the interior angles of a kite = 360°, hence

x = 360 - (82 + 82 + 140) = 360 - 304 = 56

4 0
3 years ago
What is 98.86-85.15 show me answers
tiny-mole [99]
98.86-85.15= 13.71 This is the answer to the problem. It's really easy. U just subtract and that's it.
7 0
3 years ago
An article in the Journal of Composite Materials describes the effect of delamination on thenatural frequency of beams made from
Vanyuwa [196]

Answer:

(230.21 ; 233.13)

Step-by-step explanation:

Given the data :

230.66, 233.05, 232.58, 229.48, 232.58

To calculate the 90% CI

WE obtain the mean and standard deviation of the sample data :

Mean of sample, ΣX /n = 1158.35/5 = 231.67

The standard deviation of the sample, s = 1.531 (Using calculator).

(The 90% Tcritical value, 2 sided, df = 4) = 2.132

The confidence interval, CI :

Mean ± Tcritical * s/√n

C.I = 231.67 ± (2.132 * (1.531/√5)

C. I = 231.67 ± 1.4597

(231.67 - 1.4597) ; (231.67 + 1.4597)

(230.21 ; 233.13)

3 0
3 years ago
Determine the stopping distance of a car with an initial speed of 29.97 m/s, a human reaction time of 1s, and an acceleration of
Rudik [331]

Answer:

5/18 m/s?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
In the arithmetic sequence, -12, -17, -22, -27... which term has a value of -68?​
RSB [31]

Answer:

-68 is not a term in the given sequence

Step-by-step explanation:

The given sequence is -12, -17, -22, -27...

There is a common difference of d=-17--12=-5

The explicit rule for this sequence is f(n)=-12-5(n-1)

Or f(n)=-5n-7

To find the term that has a value of -68 we equate the explicit formula and solve for n.

 -68=-5n-7

 \implies -68+7=-5n

 \implies -61=-5n

n=\frac{61}{5} =12.2

The position should be a natural number.

Since n is a decimal, it tells us that -68 is not a term in the given sequence

7 0
4 years ago
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