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prisoha [69]
3 years ago
6

What is the equation of a line that contains the point (2,1) and is perpendicular to the line: y = 3x – 4?

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0
Y = 3x - 4.....the slope here is 3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, u flip the slope and change the sign. So we will need a slope of -1/3...see how I flipped the slope of 3/1 and made it 1/3...and then changed the sign, making it -1/3.

y = mx + b
slope(m) = -1/3
(2,1)...x = 2 and y = 1
now we sub and find b, the y int
1 = -1/3(2) + b
1 = -2/3 + b
1 + 2/3 = b
3/3 + 2/3 = b
5/3 = b

so ur perpendicular equation is : y = -1/3x + 5/3
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Answer:

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Step-by-step explanation:

<u>Given: </u>

line y=3x-1

point (-3,0)

<u>Write:</u> equation of the line that is perpendicular to the given and passes through the point (-3,0)

<u>Solution:</u>

The slope of the given line is m=3

If m_1 is the slope of perpendicular line, then

m\cdot m_1=-1\\ \\3m_1=-1\\ \\m_1=-\dfrac{1}{3}

So, the equation of the needed line is y=-\dfrac{1}{3}x+b.

Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:

0=-\dfrac{1}{3}\cdot (-3)+b\\ \\0=1+b\\ \\b=-1\\ \\y=-\dfrac{1}{3}x-1

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