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MAXImum [283]
3 years ago
7

Determine the values of the parameter s for which the system has a unique​ solution, and describe the solution. sx 1 minus 2 sx

2sx1−2sx2 equals= 3 3 x 1 minus 6 sx 23x1−6sx2 equals= 5
Mathematics
1 answer:
JulijaS [17]3 years ago
6 0

Note: The equations written in this questions are not appropriately expressed, however, i will work with hypothetical equations that will enable you to solve any problems of this kind.

Answer:

For the system of equations to be unique, s can take all values except 2 and -2

Step-by-step explanation:

2sx_{1} + 4x_{2} = -3\\2x_{1} + sx_{2} = 4

\left[\begin{array}{ccc}2s&4\\2&s\end{array}\right] \left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right] = \left[\begin{array}{ccc}-3 \\6 \end{array}\right]

For the system to have a unique solution, \begin{vmatrix} 2s & 4 \\ 2 & s \end{vmatrix} \neq 0

2s^{2} -8 \neq 0\\2s^{2}\neq 8\\s^{2}\neq 4\\s \neq 2 or -2

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3 years ago
The College Student Journal (December 1992) investigated differences in traditional and nontraditional students, where nontradit
shutvik [7]

Answer:

There is a 0.13% probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

For this problem, we have that:

Based on the study results, we can assume the population mean and standard deviation for the GPA of nontraditional students is \mu = 3.5 and \sigma = 0.5.

We have a sample of 100 students, so we need to find the standard deviation of the sample, to use in the place of \sigma in the z score formula.

s = \frac{\sigma}{\sqrt{100}} = \frac{0.5}{10} = 0.05.

What is the probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65?

This is 1 subtracted by the pvalue of Z when X = 3.65. So

Z = \frac{X - \mu}{s}

Z = \frac{3.65 - 3.50}{0.05}

Z = 3

A zscore of 3 has a pvalue of 0.9987.

So, there is a 1-0.9987 = 0.0013 = 0.13% probability that the random sample of 100 nontraditional students have a mean GPA greater than 3.65.

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3 years ago
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