6th grade math help me pleaseeee...

If A(1,2), B(5,-4) and (-3,2) are the vertices of a triangle, which statement holds true?

Zigmanuir [339]

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The correct option is A.

<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.

The length of different sides are:

$AB = \sqrt{(5-1)^2+(-4-2)^2} = \sqrt{16+36} = \sqrt{52}\rm\ units$

$BC = \sqrt{(-3-5)^2+(2+4)^2} = \sqrt{64+36} = 10\rm\ units$

$AC = \sqrt{(2-2)^2+(-3-1)^2} = \sqrt{16} = 4\rm\ units$

Since the length of all the sides of the triangle is not equal it is a scalene triangle.

Hence, the correct option is A.

Learn more about Triangle:

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7 0

2 years ago

Read 2 more answers

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Thus the given expression is simplified

8 0

3 years ago

Elizabeth uses 23.25 ounces of granola and 10.5 ounces of raisins for 15 servings of trail mix.If each serving contains the same

alexdok [17]

The answer is 2.22 if you divide it. Add the ingredients then divide on how many servings.

5 0

4 years ago

Read 2 more answers

Please help, i’ll mark brainliest.

nalin [4]

Answer:

264 cu

Step-by-step explanation:

This is because you have to add it from all sides, the first prism is 144 cu and then the second one is, 120, and when you add both of those together you get 264

Thus the answer is....264

5 0

2 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE