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s2008m [1.1K]
2 years ago
15

8(3x-1)=-80 ^^ also show the check pls

Mathematics
2 answers:
mylen [45]2 years ago
8 0
8(3x-1)=-80
8•3x=24x
8•1=8
24x-8=-80
+8 +8
---------------------
24x=-72
------ -----
24 24

x=-3
iragen [17]2 years ago
7 0
X=-3

using the distribution property, plug in -3 as x
this should give you your answer.
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A right rectangular container is 10 cm wide and 24 cm long and contains water to a depth of 14cm. A stone is placed in the water
Simora [160]

Answer:

1356cm3

Step-by-step explanation:

when the stone is dropped in to the water the new height is 17.4cm(14+3.4)

find the volume when the height is 14cm and when the height is 17.4cm

24*14*17.4=4716

24*14*14=3360

then subtract the two volumes

4716-3360=1356cm3

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Since it’s a 90° angle if u draw it on a grid with the given units C would be 5 until a when measured
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3 years ago
In a certain class, the ratio of girls to boys was 5 to 4. If there are 80 boys in the class, how many students are there in all
andriy [413]

there are 180 students in the entire class


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2 years ago
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A juice recipe calls for 5 cups of grape juice for every 2 cups of peach juice are needed for a batch that uses 8 cups of peach
Ksivusya [100]

Answer: 20 cups of grape juice are needed for 8 cups of peach juice.

Step-by-step explanation:

5 times 4 is 20.

We must do this step because you need 2 cups for 1 batch, and times 4 that is 8. So then we multiplied 5 times 4.

So, 20 cups of grape juice are needed for 8 cups of peach juice.

Hope this answer helps you out!

3 0
3 years ago
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Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
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