10x^6y^3 + 20x^3y^2 / 5x^3y =
5x^3y (2x^3y^2 + 4y) / 5x^3y=
<span>2x^3y^2 + 4y
</span>
First you find what the expressions 10x^6y^3 and 20x^3y^2 have in common, and that is 5x^3y, which is the same as the denominator, so you can easily divide them and get 1.
<span>Hope you understand!
</span>
Answer:
80
Step-by-step explanation:
Initial ratio:
Teachers to students
1 : 15
Ratio after:
Teachers to students
3 : 40
The number of students did not change, so we can make the students of the initial ratio and the students of the ratio after the same.
1 : 15 = 8 : 120
3 : 40 = 9 : 120
120 units = 1200
1 unit = 
Initial teachers = 8 units = 
B. is the answer I believe since most are not functions
I got 48x
First by distributing 2x to 9-5x=
18x-10x
Then adding a 1 in front of - making -4x-36x to 4x+36x=40x
8x+40x=48x