T probability of rolling doubles after 45 tosses is 0.156
<h3>How to determine the regression equation?</h3>
To do this, we enter the data values in a graphing calculator.
From graphing calculator, we have the following summary:
- Sum of X = 550
- Sum of Y = 87
- Mean X = 55
- Mean Y = 8.7
- Sum of squares (SSX) = 8250
- Sum of products (SP) = 1375
The regression equation is
y = bx + a
Where
b = SP/SSX = 1375/8250 = 0.16667
a = MY - bMX = 8.7 - (0.17*55) = -0.46667
So, we have:
y = 0.16667x - 0.46667
Approximate
y = 0.167x - 0.467
When the number of tosses is 45, we have:
y = 0.167 * 45 - 0.467
Evaluate
y = 7.048
Approximate
y = 7
45 tosses gives 7 doubles.
So, the probability is:
P = 7/45
Evaluate
P = 0.156
Hence, the probability of rolling doubles after 45 tosses is 0.156
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Answer:
Number of people who order chicken dinner = 1
Number of people who order the steak dinner = 5
Step-by-step explanation:
Let
x = number of people who order chicken dinner
y = number of people who order the steak dinner
x + y = 6 (1)
14x + 17y = 99 (2)
From (1)
x = 6 - y
Substitute into (2)
14x + 17y = 99 (2)
14(6 - y) + 17y = 99
84 - 14y + 17y = 99
- 14y + 17y = 99 - 84
3y = 15
y = 15/3
y = 5
Substitute y = 5 into (1)
x + y = 6 (1)
x + 5 = 6
x = 6 - 5
x = 1
Number of people who order chicken dinner = 1
Number of people who order the steak dinner = 5
Let me think this through again and I will come back to you! 2.22 graph
The value of constant a is -5
Further explanation:
We will use the comparison of co-efficient method for finding the value of a
So,
Given
As it is given that
(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28
In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x
Comparing coefficient of x^3
So the value of constant a is -5
Keywords: Polynomials, factorization
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B hope that helps have good one
