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balandron [24]
3 years ago
9

An epidemic has hit Minecole City. Its population is declining 34% every hour. In just 3 hours, there are only 25,143 people lef

t in the city. What was the initial population in the city before the epidemic broke out? PLEASE HELP!!!
Mathematics
1 answer:
Vinvika [58]3 years ago
7 0
The answer is 87,455

P(x) = P(0) * nˣ
P(x) - the final population after period x
P(0) - the initial population
n - the growth factor in decimal
x - period of time

x = 3 hours
P(3) = 25,143
P(0) = ?
n = 100- 34% = 66% = 0.66


P(x) = P(0) * nˣ
25,143 = P(0) * 0.66³
25,143 = P(0) * 0.287496
P(0) = 25,143 / 0.287496
P(0) ≈ 87,455
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<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

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\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

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<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

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t = \frac{\overline{x} - \mu}{s}

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More can be learned about the t-distribution at brainly.com/question/16313918

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