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Margarita [4]
3 years ago
5

Write the equation, in standard form, of a polynomial of the least degree with integral

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

f

(

x

)

=

3

x

3

−

5

x

2

−

47

x

−

15

Explanation:

If the zero is c, the factor is (x-c).

So for zeros of

−

3

,

−

1

3

,

5

, the factors are

(

x

+

3

)

(

x

+

1

3

)

(

x

−

5

)

Let's take a look at the factor

(

x

+

1

3

)

. Using the factor in this form will not result in integer coefficients because

1

3

is not an integer.

Move the

3

in front of the x and leave the

1

in place:

(

3

x

+

1

)

.

When set equal to zero and solved, both

(

x

+

1

3

)

=

0

and

(

3

x

+

1

)

=

0

result in

x

=

−

1

3

.

f

(

x

)

=

(

x

+

3

)

(

3

x

+

1

)

(

x

−

5

)

Multiply the first two factors.

f

(

x

)

=

(

3

x

2

+

10

x

+

3

)

(

x

−

5

)

Multiply/distribute again.

f

(

x

)

=

3

x

3

+

10

x

2

+

3

x

−

15

x

2

−

50

x

−

15

Combine like terms.

f

(

x

)

=

3

x

3

−

5

x

2

−

47

x

−

15

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3/4

Step-by-step explanation:

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6 0
3 years ago
Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 12 feet a
Brrunno [24]

Answer:

Step-by-step explanation:

The student needs to check all algebraic and mathmatical calculations for errors and typos.  I'm old and have been prone to making mistakes.

Cylinder A DIAMETER 12 ft and Height 13 ft

Cylinder B DIAMETER 10 ft and Height 16 ft

After pumping How much water remains in cylinder A

Volume of a cylinder  =  π(radius)²h is the normal form since they provided the diameter I will use     Volume of a cylinder  =  π(diameter/2)²h

Water remaining in A = Volume of A  - Volume of B   =  

VolA  - VolB  =  π(D for A/2)²H of A  -   π(D for B/2)²H of B

             writing if a little more condensed

VolA  - VolB  =  π(D for A/2)²H of A  -   π(D for B/2)²H of B

    Va - Vb    =   π(Da/2)²Ha  -   π(Db/2)²Hb

                     =  π [(Da²/2²)Ha - (Db²/2²)Hb]      factored out the π

                     =  π/4 [ Da²Ha  - Db²Hb]              factored out the (1/2)²

             I can't think of any other algebraic steps

Va - Vb = Water Remaining in Container A  =  π/4 [ Da²Ha  - Db²Hb]            

            =  π/4 [ (12²)(13)  - (10²)(16)]

            =  π/4 [ (144)(13)  - (100)(16)]

            =  π/4 [ 1872 - 1600 ]

            =  π/4 [272]

            =  π [ 272/4 ]  

            =  π [ 136 / 2]

            =  π [ 68 ]

            =  π (68)

            =  213.6  ft³             rounded to the nearest tenth

I checking my answer by using  V = πr²h         r = d/2

           Va - Vb = π [ra²ha - rb²hb]

                         = π [6²(13)  - 5²(16)]

                         = π [(36)(13) - (25)(16)]

                         = π [ 468 - 400]

                         = 68 π

                         = 213.6 ft³         I got the same answer

       

            =  π

test

   

8 0
3 years ago
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